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This is solved by simultaneous equations. Perimeter = 2a + 2b = 100 where a and b are lengths of sides Area = a x b Rearranging the perimeter equation: 2a = 100 - 2b, a = 50 - b Putting this equation into the area equation: Area = (50 - b) x b = 50b - b x b Find the minimum/maximum by differentiating and setting to 0. Area' = 50 - 2b = 0, 2b = 50, b = 25 Area = 625cm sqare. when the length tends to 50, the area tends to 0. So the area can be anything from 0 to 625 cm

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Q: The perimeter of a rectangle is 100cm what could be its area?
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