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Note : sin² Φ + cos² Φ = 1 for all real Φ.

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Now, given that : cos² (6y) + sin² (6y) = y + 14

∴ 1 = y + 14 ∴differentiating w.r.t. x, ... 0 = (dy/dx) + 0

∴ dy/dx = 0 ........... Ans.___________________________________

Happy To Help !

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