25Q + P = 300, Q + P = 60Subtract: 24Q = 240 ==> Q = 10, and then P = 50 Check: 10 quarters = $2.50, + 50 cents = $3.00
10 points for Q and Z in Scrabble.
Points for "Q" in Scrabble
p=3 !
Suppose the value of whatever it is, is P in the first year and Q in the next. Then the percentage change is 100*(P - Q)/Q or, equivalently, 100*(P/Q - 1)
If p = 50 of q then q is 2% of p.
25Q + P = 300, Q + P = 60Subtract: 24Q = 240 ==> Q = 10, and then P = 50 Check: 10 quarters = $2.50, + 50 cents = $3.00
Suppose the sides of the parallelogram are of lengths p and q and let p <= q.Then either 10 < p <= sqrt(120) and 120/p <= q < 12.5 or sqrt(120) <=p <= q <= 12.5
3/p = 6 p = 3/6 = 1/2 3/q = 15 q = 3/15 = 1/5 p - q = 1/2 - 1/5 p - q = 5/10-2/10 = 3/10
It is not possible to answer this question without knowing the actual expression used in the assignment statement. The following are merely example expressions showing some of the values that could be assigned to ans: int ans, p=100, q=50; ans = p + q; // ans = 150 ans = p * q; // ans = 5000 ans = p - q; // ans = -50 ans = p / q; // ans = 2 ans = p % q; // ans = 0
If: q = -12 and p/q = -3 Then: p = 36 because 36/-12 = -3
the product of 10p (p–q) is 10p²-10pq Given: 10p (p–q) To find : the product of 10p (p–q) Solution: we have to find the product of 10p (p–q). so product of any number means the multiplication multiply (p–q). by 10p we get, =10p× (p–q) =10p×p-10p× q =10p²-10pq the product of 10p (p–q) is 10p²-10pq
10 points for Q and Z in Scrabble.
P . . Q . . (P or Q)0 . . 0 . . . 00 . . 1 . . . 11 . . 0 . . . 11 . . 1 . . . 1=================P . . Q . . NOT(P and Q)0 . . 0 . . . . 10 . . 1 . . . . 11 . . 0 . . . . 11 . . 1 . . . . 0
10 is a rational no. as rational no. is a no. which can be written in p/q form where p,q belongs to Z and q is not equal to zero. so 10/1 is a rational no. not irrational.
50
Points for "Q" in Scrabble