As can be seen, each succesive term is 2 greater than the last. We can write a rule to calculate the nth term. Here the rule equals 2n - 8. So the 20th term = (2 * 20) - 8 = 32.
If the Fibonacci sequence is denoted by F(n), where n is the first term in the sequence then the following equation obtains for n = 0.
It is the sequence of first differences. If these are all the same (but not 0), then the original sequence is a linear arithmetic sequence. That is, a sequence whose nth term is of the form t(n) = an + b
If the first two numbers are 0, 1 or -1 (not both zero) then you get an alternating Fibonacci sequence.
The pattern for the sequence 0 0 1 3 6 is that each term is obtained by adding the previous term multiplied by its position in the sequence (starting from 1). In other words, the nth term is given by n*(n-1)/2.
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
As can be seen, each succesive term is 2 greater than the last. We can write a rule to calculate the nth term. Here the rule equals 2n - 8. So the 20th term = (2 * 20) - 8 = 32.
If the Fibonacci sequence is denoted by F(n), where n is the first term in the sequence then the following equation obtains for n = 0.
The general term for the sequence 0, 1, 1, 2, 2, 3, 3 is infinite sequence.
It is the sequence of first differences. If these are all the same (but not 0), then the original sequence is a linear arithmetic sequence. That is, a sequence whose nth term is of the form t(n) = an + b
If the first two numbers are 0, 1 or -1 (not both zero) then you get an alternating Fibonacci sequence.
sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10
The pattern for the sequence 0 0 1 3 6 is that each term is obtained by adding the previous term multiplied by its position in the sequence (starting from 1). In other words, the nth term is given by n*(n-1)/2.
24 - 6n
280
This is an arithmetic progression. In general, If an A.P. has a first term 'a', and a common difference 'd' then the nth term is a + (n - 1)d. In the sequence shown in the question, the first term is 0 and the common difference is 5, therefore the nth term is, 0 + (n - 1)5. This can be rearranged to read : 5(n - 1) For example : the 7th term is 30 : 5(7 - 1) = 5 x 6 = 30.
To work out the equation of a sequence, you should first look at the differences in the sequence. In this case, the differences between the numbers are -2, -2, -2. Thus the equation for the sequence is x-2n To work out x, you need to find what the "0th term" would be, or the term that would come before 4. In this case, it would be 4+2=6. Therefore, the equation for the nth term is 6-2n