Increase of +2
20th term x 2 = 40
(take away the first 4 terms)
40 - (4 x 2) = 32
By formula method:
This is an arithmetic progression.
First term is a = --6; common difference d = +2 the expected term n = 20
By formula, tn = a + (n--1)d
Hence plugging, the required 20th term is --6 + 38 = 32
As can be seen, each succesive term is 2 greater than the last. We can write a rule to calculate the nth term. Here the rule equals 2n - 8. So the 20th term = (2 * 20) - 8 = 32.
If the Fibonacci sequence is denoted by F(n), where n is the first term in the sequence then the following equation obtains for n = 0.
It is the sequence of first differences. If these are all the same (but not 0), then the original sequence is a linear arithmetic sequence. That is, a sequence whose nth term is of the form t(n) = an + b
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 4, then 8, then 12, then 16, and so on. This pattern suggests that the nth term can be represented by the formula n^2 + n, where n is the position of the term in the sequence. So, the nth term for the given sequence is n^2 + n.
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 9, then 13, then 17, and so on. This pattern indicates that the nth term is given by the formula n^2 + n - 1. So, the nth term of the sequence 0, 9, 22, 39, 60 is n^2 + n - 1.
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
As can be seen, each succesive term is 2 greater than the last. We can write a rule to calculate the nth term. Here the rule equals 2n - 8. So the 20th term = (2 * 20) - 8 = 32.
If the Fibonacci sequence is denoted by F(n), where n is the first term in the sequence then the following equation obtains for n = 0.
To find the nth term of a sequence, we first need to identify the pattern or rule that governs the sequence. In this case, the sequence is decreasing by 6 each time. Therefore, the nth term can be represented by the formula: 18 - 6(n-1), where n is the position of the term in the sequence.
The general term for the sequence 0, 1, 1, 2, 2, 3, 3 is infinite sequence.
It is the sequence of first differences. If these are all the same (but not 0), then the original sequence is a linear arithmetic sequence. That is, a sequence whose nth term is of the form t(n) = an + b
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 4, then 8, then 12, then 16, and so on. This pattern suggests that the nth term can be represented by the formula n^2 + n, where n is the position of the term in the sequence. So, the nth term for the given sequence is n^2 + n.
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 9, then 13, then 17, and so on. This pattern indicates that the nth term is given by the formula n^2 + n - 1. So, the nth term of the sequence 0, 9, 22, 39, 60 is n^2 + n - 1.
The given sequence is an arithmetic sequence with a common difference of 5. To find the nth term of an arithmetic sequence, we use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1 = 0) and the common difference (d = 5). Therefore, the nth term of the sequence is (a_n = 0 + (n-1)5 = 5n - 5).
If the first two numbers are 0, 1 or -1 (not both zero) then you get an alternating Fibonacci sequence.
sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10
The sequence of (3n) represents a series of numbers generated by multiplying the integer (n) by 3. Specifically, for (n = 0, 1, 2, 3, \ldots), the sequence is (0, 3, 6, 9, 12, \ldots). This is an arithmetic sequence where each term increases by 3, starting from 0. The general term can be expressed as (3n) for (n = 0, 1, 2, \ldots).