pi2
Cube it. 3 x 3 x 3 = 27 cubic units
42
(x + 3)(x - 1)(x + 1)
3 x 3 x 3 = 27 27 is the cube of 3. 3 is the cube root of 27.
pi2
Cube it. 3 x 3 x 3 = 27 cubic units
42
The volume of a cube is L3 where L is the side length. If L = x + 2 then the volume is (x + 2)3 = x3 + 6x2 + 12x + 8.
It can be simplified to: 3x3+16x2+41x+4 but divided by what is not given
(X minus the cube root of fifteen) times (x squared plus the cube root of fifteen plus fifteen to the two thirds power)
(x + 3)(x - 1)(x + 1)
x^3+y^3 Cube root of the first, x plus cube root of the last, y times What it takes to make the first number, x^2 Opposite sign, - Product of the two cube roots, -xy Then what it takes to make the last. (x+y)(X^2-xy+y^2)
The square root of 9 is the number you times by itself to get 9, so that's 3. Then to cube it you do 3 x 3 x 3 which is 27.
3 x 3 x 3 = 27 27 is the cube of 3. 3 is the cube root of 27.
If the negative number is "-a", then you can say the cube root is "-(cube root of a)" Because if you cube a negative number, you get a negative number. So if you cube root a negative number, you get a negative number. Ex) cube root of -8 = -2 Because (-2)^3 = -8 But if you want to find the complex cube roots, you can make an equation: "x^3=-a" or "x^3+a=0" We know one of the roots is "-(cube root of a)" so you can factor the equation by (x+(cube root of a)) And then you use the quadratic formula for the quadratic equation you're left with. Ex) x^3=-8 or x^3+8=0 Since -2 is a root, factor it by (x+2) x^3+8=(x+2)(x^2-2x+4) Using the quadratic formula, you get "1+i√3" and "1-i√3" Therefore the three cube roots of -8 is <"-2", "1+i√3", "1-i√3">
If: x+3 = 3+7 Then: x = 7