(x + 3)^(3) =
(x +3)(x + 3)(x +3) =
(x^2 + 6x 9)(x + 3) =
x^3 + 6x^2 + 9x + 3x^2 + 18x + 27
Collect like terms
x^3 + 9x^2 + 27x + 27
Done!!!!!
pi2
Cube it. 3 x 3 x 3 = 27 cubic units
42
There is no such thing as a cube route. The cube root of -3 is -1.4422 (approx).There is no such thing as a cube route. The cube root of -3 is -1.4422 (approx).There is no such thing as a cube route. The cube root of -3 is -1.4422 (approx).There is no such thing as a cube route. The cube root of -3 is -1.4422 (approx).
(x + 3)(x - 1)(x + 1)
pi2
Cube it. 3 x 3 x 3 = 27 cubic units
42
The volume of a cube is L3 where L is the side length. If L = x + 2 then the volume is (x + 2)3 = x3 + 6x2 + 12x + 8.
It can be simplified to: 3x3+16x2+41x+4 but divided by what is not given
There is no such thing as a cube route. The cube root of -3 is -1.4422 (approx).There is no such thing as a cube route. The cube root of -3 is -1.4422 (approx).There is no such thing as a cube route. The cube root of -3 is -1.4422 (approx).There is no such thing as a cube route. The cube root of -3 is -1.4422 (approx).
(X minus the cube root of fifteen) times (x squared plus the cube root of fifteen plus fifteen to the two thirds power)
If log(x) = y then log(x3) = 3*log(x) = 3*y so that x3 = antilog(3*y) So, to find the cibe of x 1) find log x 2) multiply it by 3 3) take the antilog of the result.
(x + 3)(x - 1)(x + 1)
x^3+y^3 Cube root of the first, x plus cube root of the last, y times What it takes to make the first number, x^2 Opposite sign, - Product of the two cube roots, -xy Then what it takes to make the last. (x+y)(X^2-xy+y^2)
The square root of 9 is the number you times by itself to get 9, so that's 3. Then to cube it you do 3 x 3 x 3 which is 27.
If the negative number is "-a", then you can say the cube root is "-(cube root of a)" Because if you cube a negative number, you get a negative number. So if you cube root a negative number, you get a negative number. Ex) cube root of -8 = -2 Because (-2)^3 = -8 But if you want to find the complex cube roots, you can make an equation: "x^3=-a" or "x^3+a=0" We know one of the roots is "-(cube root of a)" so you can factor the equation by (x+(cube root of a)) And then you use the quadratic formula for the quadratic equation you're left with. Ex) x^3=-8 or x^3+8=0 Since -2 is a root, factor it by (x+2) x^3+8=(x+2)(x^2-2x+4) Using the quadratic formula, you get "1+i√3" and "1-i√3" Therefore the three cube roots of -8 is <"-2", "1+i√3", "1-i√3">