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Whai is the solution to Ln 2x plus 9 equals ln 5x?
That all depends.Is it:ln (2x+9) = ln (5x)If it is, the solution can be found by solving 2x+9 = 5x, in which case the answer is x = 3.
Do any positive real numbers alpha and beta exist such that lnalpha times beta equals lnalpha plus lnbeta and if so what are they?
I assume the question is NOT about ln(a*b) = ln(a) + ln(b) because that is true for all positive real a and b. Instead, you want a solution to ln(a) * b = ln(a) + ln(b) or, ln(a) * (b-1) = ln(b) ln(a) = ln(b)/(b-1) ln(a) = ln[b1/(b-1)] Exponentiating, a = b1/(b-1) For any real number b > 1, a given by the above equation will meet your requirements.
What is the derivative of ln 1?
It is equal to 0
Solve or x 2 ln 9 plus 2 ln 5 equals 2 ln x minus 3?
2 ln(9) + 2 ln(5) = 2 ln(x) - 3ln(81) + ln(25) = ln(x2) - 37.61332 = ln(x2) - 3ln(x2) = 10.61332ln(x) = 5.30666x = e5.30666 = 201.676 (rounded)
How do you solve ln 5 plus ln x equals 1?
5 + (-4) = 1 x = -4
Why does ln x plus 2 equal 2 plus ln x?
Because of the commutative property of addition.
Whai is the solution to Ln 2x plus 9 equals ln 5x?
That all depends.Is it:ln (2x+9) = ln (5x)If it is, the solution can be found by solving 2x+9 = 5x, in which case the answer is x = 3.
What is equivalent to ln 6 plus ln 4?
You can also write this as ln(6 times 4)
What does ln 1 equal?
ln 1 = 0 e0=1
Do any positive real numbers alpha and beta exist such that lnalpha times beta equals lnalpha plus lnbeta and if so what are they?
I assume the question is NOT about ln(a*b) = ln(a) + ln(b) because that is true for all positive real a and b. Instead, you want a solution to ln(a) * b = ln(a) + ln(b) or, ln(a) * (b-1) = ln(b) ln(a) = ln(b)/(b-1) ln(a) = ln[b1/(b-1)] Exponentiating, a = b1/(b-1) For any real number b > 1, a given by the above equation will meet your requirements.
How would you solve ln 4 plus 3 ln x equals 5 ln 2?
Ln 4 + 3Ln x = 5Ln 2 Ln 4 + Ln x3= Ln 25 = Ln 32 Ln x3= Ln 32 - Ln 4 = Ln (32/4) = Ln 8= Ln 2
What is the derivative of ln 1?
It is equal to 0
How do you find value ln 2.33?
To find ln 2.33, you need a calculator. It is the solution of the equation e^x = 2.33. ln 2.33 = 0.84586 (using a calculator)
What is the value of loge if base is not equal to e?
You can calculate log to any base by using: logb(x) = ln(x) / ln(b) [ln is natural log], so if you have logb(e) = ln(e) / ln(b) = 1 / ln(b)
Solve or x 2 ln 9 plus 2 ln 5 equals 2 ln x minus 3?
2 ln(9) + 2 ln(5) = 2 ln(x) - 3ln(81) + ln(25) = ln(x2) - 37.61332 = ln(x2) - 3ln(x2) = 10.61332ln(x) = 5.30666x = e5.30666 = 201.676 (rounded)
How do you solve ln 5 plus ln x equals 1?
5 + (-4) = 1 x = -4
What is the Natural log of 0?
The answer is "no solution." ln(0) means e^x=0, and nothing raised to any power can ever equal zero. The domain of y=lnx is (0,∞) and the range is (-∞,∞).
