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What is the slope m of a line that is perpendicular to the line represented by x 7?
To find the slope ( m ) of a line that is perpendicular to another line, you need to know the slope of the original line. However, the equation you provided, "x 7," seems incomplete. If you meant a line in the form ( y = mx + b ) where ( m ) is the slope, you can find the perpendicular slope by taking the negative reciprocal of ( m ). If you clarify the original line's equation, I can provide a more specific answer.
How do you write an equation for a perpendicular line?
To write an equation for a perpendicular line, first determine the slope of the original line. If the slope of the original line is ( m ), the slope of the perpendicular line will be the negative reciprocal, ( -\frac{1}{m} ). Using the point-slope form ( y - y_1 = m(x - x_1) ), where ( (x_1, y_1) ) is a point on the new line, substitute the perpendicular slope and point to derive the equation of the perpendicular line. Finally, you can rearrange it into slope-intercept form, ( y = mx + b ), if desired.
Which equation is a line that is perpendicular to the line of 8x 1 algebra 2?
To find a line that is perpendicular to the line represented by the equation (8x + b) (assuming (b) is a constant), we first need to determine the slope of the original line. The slope of the line (y = 8x + b) is 8. The slope of a line that is perpendicular to this would be the negative reciprocal, which is (-\frac{1}{8}). Therefore, a possible equation for a line perpendicular to it could be (y = -\frac{1}{8}x + c), where (c) is any constant.
What equation is perpendicular to y-8x-6?
To find an equation that is perpendicular to ( y - 8x - 6 = 0 ), we first determine the slope of the given line. Rearranging it to slope-intercept form ( y = 8x + 6 ) reveals that the slope is 8. The slope of a line perpendicular to this would be the negative reciprocal, which is ( -\frac{1}{8} ). Therefore, an equation perpendicular to the original line can be expressed in point-slope form as ( y - y_1 = -\frac{1}{8}(x - x_1) ), where ( (x_1, y_1) ) is any point on the original line.
What is the slope of a line perpendicular to the line with equation y 4x 5?
If you mean: y = 4x+5 then the perpendicular slope is -1/4
What is the slope m of a line that is perpendicular to the line represented by x 7?
To find the slope ( m ) of a line that is perpendicular to another line, you need to know the slope of the original line. However, the equation you provided, "x 7," seems incomplete. If you meant a line in the form ( y = mx + b ) where ( m ) is the slope, you can find the perpendicular slope by taking the negative reciprocal of ( m ). If you clarify the original line's equation, I can provide a more specific answer.
What is the slope of the perpendicular to the line whose equation is y equals 5x-7?
12
How do you write an equation for a perpendicular line?
To write an equation for a perpendicular line, first determine the slope of the original line. If the slope of the original line is ( m ), the slope of the perpendicular line will be the negative reciprocal, ( -\frac{1}{m} ). Using the point-slope form ( y - y_1 = m(x - x_1) ), where ( (x_1, y_1) ) is a point on the new line, substitute the perpendicular slope and point to derive the equation of the perpendicular line. Finally, you can rearrange it into slope-intercept form, ( y = mx + b ), if desired.
What is the perpendicular equation that meets the line of 2 3 and 5 7 at its midpoint showing key aspects of work?
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
What is the slope of a line that is perpendicular to the line whose equation is 2y x - 1?
Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.
Which equation is a line that is perpendicular to the line of 8x 1 algebra 2?
To find a line that is perpendicular to the line represented by the equation (8x + b) (assuming (b) is a constant), we first need to determine the slope of the original line. The slope of the line (y = 8x + b) is 8. The slope of a line that is perpendicular to this would be the negative reciprocal, which is (-\frac{1}{8}). Therefore, a possible equation for a line perpendicular to it could be (y = -\frac{1}{8}x + c), where (c) is any constant.
What equation is perpendicular to y-8x-6?
To find an equation that is perpendicular to ( y - 8x - 6 = 0 ), we first determine the slope of the given line. Rearranging it to slope-intercept form ( y = 8x + 6 ) reveals that the slope is 8. The slope of a line perpendicular to this would be the negative reciprocal, which is ( -\frac{1}{8} ). Therefore, an equation perpendicular to the original line can be expressed in point-slope form as ( y - y_1 = -\frac{1}{8}(x - x_1) ), where ( (x_1, y_1) ) is any point on the original line.
What is the slope of a line perpendicular to the line with equation y 4x 5?
If you mean: y = 4x+5 then the perpendicular slope is -1/4
What is the slope of a line perpendicular to the line with equation y 5x- 2?
If you mean: y = 5x-2 then the perpendicular slope is -1/5
Perpendicular line of y23x 5?
To find the equation of a line that is perpendicular to ( y = 23x + 5 ), we first identify the slope of the given line, which is 23. The slope of a line that is perpendicular to it is the negative reciprocal, so it would be ( -\frac{1}{23} ). If we have a point through which the perpendicular line passes, we can use the point-slope form ( y - y_1 = m(x - x_1) ) to write the equation, where ( m = -\frac{1}{23} ).
What is the equation of a line that is perpendicular to and passes through the point (6 8)?
To find the equation of a line that is perpendicular to another line, you first need the slope of the original line. If the slope of the original line is ( m ), then the slope of the perpendicular line will be ( -\frac{1}{m} ). Assuming you know the slope ( m ), you can then use the point-slope form of a line, ( y - y_1 = m(x - x_1) ). For the point (6, 8), the equation becomes ( y - 8 = -\frac{1}{m}(x - 6) ) if you replace ( m ) with the negative reciprocal of the original slope.
What is an equation for a line perpendicular to y4x 3 that passes through the point (-85)?
To find the equation of a line perpendicular to ( y = 4x + 3 ), we first determine the slope of the given line, which is 4. The slope of a line perpendicular to it is the negative reciprocal, so it would be ( -\frac{1}{4} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with the point (-8, 5) and the slope ( -\frac{1}{4} ), the equation becomes ( y - 5 = -\frac{1}{4}(x + 8) ). Simplifying this gives the equation of the perpendicular line.
