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Which equation is a line that is perpendicular to the line of 8x 1 algebra 2?
To find a line that is perpendicular to the line represented by the equation (8x + b) (assuming (b) is a constant), we first need to determine the slope of the original line. The slope of the line (y = 8x + b) is 8. The slope of a line that is perpendicular to this would be the negative reciprocal, which is (-\frac{1}{8}). Therefore, a possible equation for a line perpendicular to it could be (y = -\frac{1}{8}x + c), where (c) is any constant.
What is the slope of a line perpendicular to the line with equation y 4x 5?
If you mean: y = 4x+5 then the perpendicular slope is -1/4
What equation is perpendicular to y-8x-6?
To find an equation that is perpendicular to ( y - 8x - 6 = 0 ), we first determine the slope of the given line. Rearranging it to slope-intercept form ( y = 8x + 6 ) reveals that the slope is 8. The slope of a line perpendicular to this would be the negative reciprocal, which is ( -\frac{1}{8} ). Therefore, an equation perpendicular to the original line can be expressed in point-slope form as ( y - y_1 = -\frac{1}{8}(x - x_1) ), where ( (x_1, y_1) ) is any point on the original line.
What is the slope of a line that is perpendicular to the line represented by the equation y-5x equals 5?
The slope is -0.2
What is an equation for a line perpendicular to y4x 3 that passes through the point (-85)?
To find the equation of a line perpendicular to ( y = 4x + 3 ), we first determine the slope of the given line, which is 4. The slope of a line perpendicular to it is the negative reciprocal, so it would be ( -\frac{1}{4} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with the point (-8, 5) and the slope ( -\frac{1}{4} ), the equation becomes ( y - 5 = -\frac{1}{4}(x + 8) ). Simplifying this gives the equation of the perpendicular line.
What is the slope of the perpendicular to the line whose equation is y equals 5x-7?
12
What is the slope of a line that is perpendicular to the line whose equation is 2y x - 1?
Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.
What is the perpendicular equation that meets the line of 2 3 and 5 7 at its midpoint showing key aspects of work?
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
What is the slope of a line perpendicular to the line with equation y 5x- 2?
If you mean: y = 5x-2 then the perpendicular slope is -1/5
What is the slope of a line perpendicular to the line with equation y 4x 5?
If you mean: y = 4x+5 then the perpendicular slope is -1/4
Which equation is a line that is perpendicular to the line of 8x 1 algebra 2?
To find a line that is perpendicular to the line represented by the equation (8x + b) (assuming (b) is a constant), we first need to determine the slope of the original line. The slope of the line (y = 8x + b) is 8. The slope of a line that is perpendicular to this would be the negative reciprocal, which is (-\frac{1}{8}). Therefore, a possible equation for a line perpendicular to it could be (y = -\frac{1}{8}x + c), where (c) is any constant.
What equation is perpendicular to y-8x-6?
To find an equation that is perpendicular to ( y - 8x - 6 = 0 ), we first determine the slope of the given line. Rearranging it to slope-intercept form ( y = 8x + 6 ) reveals that the slope is 8. The slope of a line perpendicular to this would be the negative reciprocal, which is ( -\frac{1}{8} ). Therefore, an equation perpendicular to the original line can be expressed in point-slope form as ( y - y_1 = -\frac{1}{8}(x - x_1) ), where ( (x_1, y_1) ) is any point on the original line.
What is the slope of a line that is perpendicular to the line represented by the equation y-5x equals 5?
The slope is -0.2
What line is perpendicular to 4x-3y12?
The equation has been distorted in the question (as usual on this site). The general idea is to solve the equation for "y"; read off the slope from the resulting equation; then divide minus 1 by this slope to get the slope of the perpendicular line.
Find the equation of a straight line perpendicular to the line 4y-3x12?
There are infinitely many lines perpendicular to this line. All of them have the slope of -4/3, if that fact is of any help to you.
Which equation represents a line perpendicular to the graph of 3x-6y12?
Solve the line equation for "y", to get it in slope-intercept form. You can immediately read the slope from this equation.Divide -1 by (slope of this first line) to get the slope of the second line - the one perpendicular to the given line. Write an equation for any line with this slope.
How do you write the equation for a perpendicular line?
Take the negative reciprocal of the lines slope you want it to be perpendicular to. For example y = 3x +2; perpendicular line slope is -1/3.
