Q: Find the perimeter of a square if the length of its diagonal is 12 inches Round to the nearest tenth?

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Approximately 10 inches.

it is impossible for a diagonal of a rhombus to be the same length as its perimeter

The diagonal length is about 18.44 inches.

Using Pythagoras' theorem: 162+122 = 400 and the square root of this is 20 (the diagonal) Therefore: 16+12+20 = a perimeter of 48 inches

Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]

Related questions

Approximately 10 inches.

it is impossible for a diagonal of a rhombus to be the same length as its perimeter

Diagonal = sqrt(36 + 25) ie sqrt 61 which is 7.8 inchesto the nearest tenth.

The length of the other diagonal works out as 12cm

The length of one diagonal is not sufficient to determine its sides and so its perimeter.

The diagonal length is about 18.44 inches.

Using Pythagoras' theorem: 162+122 = 400 and the square root of this is 20 (the diagonal) Therefore: 16+12+20 = a perimeter of 48 inches

The diagonal length = 7.07 inches.

Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]

The perimeter of this square is 56.569 meters.

Diagonal of a square of side s is given by: d = 21/2s We have, d = 13 inches So, using the above formula we get, s = d/21/2 = 13/21/2 inches = 9.193 inches

The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.