Let the unknown number be x: 9x-15 = 39 9x = 39+15 9x = 54 Divide both sides by 9 to find the value of x: x = 6
9x - 20 = 7 9x = 27 x = 3
ANSWER: -4X2 -8X-4x (x+2)= (-4x * x) + (-4x*2)= -4X2 -8X
9x+7
(9x)2 = 81x2
The discriminant is 33.
sure it does... that would be true
Let the unknown number be x: 9x-15 = 39 9x = 39+15 9x = 54 Divide both sides by 9 to find the value of x: x = 6
If you mean (9x-8y)(9x+8y) then it is 81x^2 minus 64y^2
Expressed algebraically, this is equal to 9x.
Dividend: x3+4x2-9x-36 Divisor: x+3 Quotient: x2+x-12
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
9x - 20 = 7 9x = 27 x = 3
32 minus the product of 9 and a number is 140 the answer is 12. 32-9x=140 9x=108 x=12
ANSWER: -4X2 -8X-4x (x+2)= (-4x * x) + (-4x*2)= -4X2 -8X
9x+7
(9x)2 = 81x2