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2y = 8x - 3 divide by 2 to both sidesy = 4x - 3/2 (this is the slope-intercept form of the equation, where slope is 4)The slope is 4.
3/7
y-4=3/2(x-7)
The slope of the line passing through the points (-4, -6) and (-3, -1) can be calculated using the formula: slope = (change in y)/(change in x). Substituting the given coordinates, we find that the slope is 5/1, or simply 5.
Points: (-4, 0) and (3, -3) Slope: -3/7
what is through (-3 , 2), slope -4 =
Points: (-3, -3) and (4, -3) Slope: (-3--3)/(-3-4) = 0
2y = 8x - 3 divide by 2 to both sidesy = 4x - 3/2 (this is the slope-intercept form of the equation, where slope is 4)The slope is 4.
3/7
how to find the slope of the line between the two points (-1,2) and (3, -6). can you plaese show how
Points: (4, 3) and (-3, -4) Slope: (-4-3)/(-3-4) = 1
y-4=3/2(x-7)
The slope of the line passing through the points (-4, -6) and (-3, -1) can be calculated using the formula: slope = (change in y)/(change in x). Substituting the given coordinates, we find that the slope is 5/1, or simply 5.
The slope of a line that has the points 3, (-4), and has a slope of 2 is 2.
To find the slope between two points: slope = change_in_y/change_in_x Thus for the points (4, 5) and (6, 8), the slope between them is given by: slope = (8-5)/(6-4) = 3/2 = 1½ = 1.5
Points: (-4, 0) and (3, -3) Slope: -3/7
answer is y=(4/3)-(2x/3)