10x + -9 = 59
can be rewritten as
10x - 9 = 59
add 9 to both sides
10x = 68
divide both sides by 10
x = 6.8
8
Wonderful. Thanks for sharing. If we had another equation in addition to that one, then we could find unique values for 'x' and 'y' that satisfy both. With only this equation, there are an infinite number of pairs of values that satisfy it, just as long as y = 0.75x + 2.75 .
x = 5 and y = -8 Solved by forming a simultaneous equation and eliminating y in order to find the values of x and y.
P2 + 13p - 30 = 0 Answer: p= -15, p = 2
A solution means: Show the numerical values of 'x' and 'y'. You can't find either one with only a single equation. You need another one. When you have two equations, you can find values for both 'x' and 'y'.
8
Find an equation of variation where y varies directly as x. One pair of values is y = 80 when x = 40
that would be limited to 3 and -3 for values of x
-0.82 , -4.82
-36
Find values for the variable that satisfy the equation, that is if you replace those values for the variable into the original equation, the equation becomes a true statement.
Wonderful. Thanks for sharing. If we had another equation in addition to that one, then we could find unique values for 'x' and 'y' that satisfy both. With only this equation, there are an infinite number of pairs of values that satisfy it, just as long as y = 0.75x + 2.75 .
n = 3/2, n = 2
x = 5 and y = -8 Solved by forming a simultaneous equation and eliminating y in order to find the values of x and y.
Replace a value for x, then solve for y, to find the corresponding value for y. Repeat for other values of x.
What is the answer
P2 + 13p - 30 = 0 Answer: p= -15, p = 2