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f(x) = -2x2 + 2x + 8

∴ f'(x) = -4x + 2

Let f'(x) = 0:

0 = -4x + 2

∴ 4x = 2

∴ x = 0.5

Now find the corresponding value:

f(0.5) = -2(0.5)2 + 2(0.5) + 8

= -0.5 + 1 + 8

= 8.5

So the vertex of this parabola occurs at the point (0.5, 8.5)

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Q: Find the vertex of -2x2 plus 2x plus 8?
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