First we need to understand that consecutive integers means integers such that each one is 1 bigger than the one before it. So 3 and 4 are consecutive.
Now if we let x be the first integer. The next is 1 bigger so it is x+1 and the third is 1 bigger than the second so it is x+2.
Now we are told the sum if 51 greater than the smallest number.
so we have x+x+1+x+2=3x+3=Sum
But we know that sum is 51 greater than x, so we write
3x+3=x+51
Solving we find:
2x=48
and x=24.
So the numbers are
24,25, and 26.
The sum is 75 which is 51 more than 24 so we are done.
The smallest is 121.
consecutive integers
The smallest six consecutive composite integers are:90, 91, 92, 93, 94, 95.(And 96 is also composite, for a run of seven consecutive.)Is that what you were asking ?
The integers are 47, 49, 51, and 53. 47 * 53 = 2491
1 is the smallest positive integer. But if you include negative integers, there is no smallest.
The smallest is 121.
59,61,63,65 It is 59
consecutive integers
For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1
"Consecutive" integers are integers that have no other integer between them.
The sum of three consecutive integers is -72
The smallest six consecutive composite integers are:90, 91, 92, 93, 94, 95.(And 96 is also composite, for a run of seven consecutive.)Is that what you were asking ?
The integers are 47, 49, 51, and 53. 47 * 53 = 2491
1 is the smallest positive integer. But if you include negative integers, there is no smallest.
Let x equal the smallest integer. The sum will be 3x + 6
The first integer is 17.
the sum of two consecutive integers is -241, what is the larger integer?