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Q: The sum of four consecutive odd integers is 248. What is the smallest integer?
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The sum of four consecutive integers is 2 What is the smallest of the four integers?

The smallest is -1


The sum of four consecutive odd integers is 200. What is the product of the smallest integer and the largestinteger?

The integers are 47, 49, 51, and 53. 47 * 53 = 2491


Is it possible for four consecutive integers whose sum is an odd integer?

No.


Find 3 consecutive even integers if the product of the first integer and two two less than the second integer is four more than five times the third integer and what is the let statement?

The let statement is: let the smallest of the three integers be x.


What is the sum of 4 consecutive integers?

If n is the smallest of the four integers, their sum is 4n+6.


The sum of 2 consecutive odd integers is 244 What is the sum of the smaller integer?

The sum is four.


What is the sum of four consecutive even integers is 2 more than five times the first integer?

The integers would begin with 10.


Find three positive consecutive odd integers such that the square of the middle integer increased by four times the largest integer is 173?

9,11,13


Four consecutive odd integers have a sum 80 what is the least of these integers?

17 , 19 , 21 and 23 are the odd integers whose sum is 80 and the least integer is 17


Find three consecutive even integers such that if the largest integer is subtracted from four times the smallest the result is 4 more than twice the middle integer?

If the largest integer is subtracted from four times the smallest, the result is 4 more than twice the middle integer. Let the smallest integer be x, then the others are x + 2 and x+ 4. Therefore 4x - (x + 4) = 2 (x + 2 ) + 4 Expanding, we get 4x -x -4 = 2x + 4 + 4 Gathering terms: x = 12 Thus the three integers are 12, 14 and 16.


Find four consecutive integers such that the sum of the second and fourth is 132 show the work?

Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.


Find three consecutive even integers such that if the largest integer is subtracted from four times the smallest the result is 8 more than twice the middle integer?

Suppose the middle integer is 2a. Then the smallest is 2a-2 and the biggest is 2a+2. 4 times the smallest is 8a-8 So largest subtracted from the smallest is (8a-8) - (2a+2) = 6a-10 So, 6a-10 = 2*2a = 4a so that 2a = 10 So the integers are 8, 10 and 12.