Let x be the first integer; x+1 is the second integer and x+2 is the third integer. Add them together as stated in the problem; x+(x+1)+(x+2)=21. 3X+3=21. 3x=18 or x=6; x+1=7 & x+2=8; 6, 7, & 8.
There are no three consecutive odd integers who's sum equals 13.
The integers are -1, 1 and 3.
The three integers are -27, -26 and -25.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
20,21 and 22 are three consecutive integers whose sum is 63. 20+21+22
There is no set of three consecutive integers whose sum is 71.
There are no three consecutive odd integers who's sum equals 13.
The integers are -1, 1 and 3.
The three integers are -27, -26 and -25.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
20,21 and 22 are three consecutive integers whose sum is 63. 20+21+22
No. There is no set of three consecutive even integers with a sum of 40.
16,17,18
11,12,13
The integers are -16 and -14.
The integers are 40, 41 and 42.
To find three consecutive integers whose sum is 186, let the first integer be ( x ). The next two integers can be expressed as ( x + 1 ) and ( x + 2 ). The equation for their sum is ( x + (x + 1) + (x + 2) = 186 ). Simplifying this gives ( 3x + 3 = 186 ), leading to ( 3x = 183 ) and ( x = 61 ). Therefore, the three consecutive integers are 61, 62, and 63.