Find three consecutive integers whose sum is 21 and show the equation?

Answer 1

Let x be the first integer; x+1 is the second integer and x+2 is the third integer. Add them together as stated in the problem; x+(x+1)+(x+2)=21. 3X+3=21. 3x=18 or x=6; x+1=7 & x+2=8; 6, 7, & 8.

Answer 2

Let x be the first integer. Then the second and third consecutive integers would be x + 1 and x + 2, respectively. The equation is x + (x + 1) + (x + 2) = 21.