Let the three numbers in geometric progression be ( a, ar, ar^2 ). The sum can be expressed as ( a(1 + r + r^2) = 28 ) and the product as ( a^3 r^3 = 512 ). From the product, we find ( a r = 8 ), allowing us to express ( a ) as ( \frac{8}{r} ). Substituting this into the sum equation leads to the system of equations that can be solved to find ( a ) and ( r ), yielding the numbers 4, 8, and 16.
19
8 and 8
8 and 5
They are: 2 and 140
3 and 84.
24,25,26
Three and Seven
19
When you have this kind of question, try to break it down, maybe first by a 2 or 3 or 10. For your question, find 3 numbers whose product is 320, the answer is 4x8x10=320. So the 3 numbers are 4, 8, and 10.
find two positive numbers whose product is a maximum. 1.) the sum is s.
It means write down three pairs of numbers that are relatively prime like 4 and 9, 5 and 6, 13 and 25
The numbers are 18 and 20.
8 and 8
9 and 6
you are a nerd
10 and 3
8 and 5