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Let the three numbers in geometric progression be ( a, ar, ar^2 ). The sum can be expressed as ( a(1 + r + r^2) = 28 ) and the product as ( a^3 r^3 = 512 ). From the product, we find ( a r = 8 ), allowing us to express ( a ) as ( \frac{8}{r} ). Substituting this into the sum equation leads to the system of equations that can be solved to find ( a ) and ( r ), yielding the numbers 4, 8, and 16.

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AnswerBot

1d ago

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