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What is the probability of getting an ace in a pack of 52 cards?
The probability is 0 if you pick the the card from one end of a mint pack (2 of clubs) and 1 if you pick it from the other end (A spades). Also, if you pick 49 cards without replacement, the probability is 1. So, the answer depends on how many cards are drawn, and whether or not they are drawn from a well shuffled pack. The probability of getting an ace when one card is randomly picked from a pack is 4/52 = 1/13.
What is the probability of choseing a king or king from a deck of 52?
The probability of getting a king in a one card draw from a deck of 52 cards is .077 or 1 chance in 13. The probability of getting a king and one other specific denomination, such as a queen, is .154, or one chance in between 6 and 7.
How many possible hands are there for getting 4 cards in the same suit with the other cards in any other random suit?
The odds of getting 4 cards in any particular suit (for example, hearts) would be:1/4*1/4*1/4*1/4=1/256.The odds of getting 4 cards of the same suit (any suit) would be 4x greater:1/256*4=1/64Because it doesn't matter what the last card is, the probability is 1/64.
What is the probability of being dealt a Blackjack?
When the deck is full, this probability is 4/52 (the probability of getting one of 4 aces) times 16/51 (the probability of getting one of 16 kings, queens, jacks, or tens) times 2 (the number of orders in which you could get these cards: ace first, or ace second). This comes out to 32/663, or about 4.83%. Of course, this probability changes as the game progresses: it decreases when any of the tens, jacks, queens, kings, or aces get discarded, but increases when other cards get discarded. This change is unpredictable, but its expected value is 0; this is a complicated concept to explain, but it means that on average, the probability will go up as much as it goes down. Also, the probability is still 32/663 at any point in the game if you have no information whatsoever about what cards came up before: if you forgot every card you saw, or if you just joined the game.
What is the probability of drawing two black sevens in succession?
The probability of drawing one black seven from a standard deck of cards is 2/52 = 1/26. The probability of drawing the other black seven from the remaining 51 cards is 1/51. Therefore the probability of drawing both black sevens from a deck of cards = 1/26 x 1/51 = 1/1326 ~ 0.000754 (3sf).
What is the probability of not getting a club in a deck of 52 cards?
The probability of not getting a club is the same as the probability of getting one of the other suits. There are (52-13)=39 such possibilities out of 52. Hence the probability is 39/52=3/4.
What is the probability of getting a heart out of a pack of cards?
If the pick is completely random, the deck is a standard deck and there are no jokers or any other cards other than the standard 52, the probability is 1/4
What is the probability of getting a king then a queen in a full deck of cards?
4/52 * 4/51 or about .006 This is assuming no other cards were drawn beforehand.
What is the probability of getting an ace in a pack of 52 cards?
The probability is 0 if you pick the the card from one end of a mint pack (2 of clubs) and 1 if you pick it from the other end (A spades). Also, if you pick 49 cards without replacement, the probability is 1. So, the answer depends on how many cards are drawn, and whether or not they are drawn from a well shuffled pack. The probability of getting an ace when one card is randomly picked from a pack is 4/52 = 1/13.
What is the probability of choseing a king or king from a deck of 52?
The probability of getting a king in a one card draw from a deck of 52 cards is .077 or 1 chance in 13. The probability of getting a king and one other specific denomination, such as a queen, is .154, or one chance in between 6 and 7.
What is the probability of you getting a 4 of diamonds?
The probability of pulling a four of diamonds from a standard deck of playing cards with the jokers removed is 1:52, the same as pulling any other individual card from the deck.
If a coin is tossed and then a dice is rolled what is the probability of getting a 5 on the dice given that the coin landed tails up?
These are independent one has no bearing on the other
What are the odds against 26 consecutive hands without so much as a pair in a five-player game of Texas hold 'em?
The probability of no player ever getting a pair with 5 players of Texas Hold 'Em in 26 hands is 1.4937 x 10-8, but see the note at the bottom. A five-player game of Texas Hold 'Em has 15 cards in play on each hand; the two down cards for each player, and the 5 common up cards. The probability of one of the down cards matching the other down card or one of the five up cards is 6 in 52 or 0.11538. The probability of one of the up cards matching one of the four other up cards is 4 in 52 or 0.076923. Invert these probabilities, and you get the probability of not matching: 46 in 52 for the down card, and 12 in 13 for the up card. Multiply these two together, and you get the probability of 552 in 676 or 0.81657 that one player does not have a pair. To determine the probability that no player has a pair, include the four other down card probabilities in the calculation. The up card probability is common to all players, so you only count that once. You get a probability of 2471555712 in 4942652416 or 0.50005 that no one has a pair in one game. To determine the probability that no player has a pair in 26 games, simply raise that to the 26th power, giving a probability of 1.4937 x 10-8 (0.000000014937) that no one gets a pair in 26 games. Note that this does not include the probability of someone not getting a flush or straight - it only gives the probability of no one ever getting a pair, and the result is so low as to be practically impossible.
What is the probability of not being dealt a queen in a 52 card deck?
The answer will depend on the exact situation.If you are dealt a single card, the probability of that single card not being a queen is 12/13 - assuming you have no knowledge about the other cards.Here is another example. If you already hold three queens in your hand (and no other cards have been dealt), the probability of the next card being dealt being a queen is 1/49, so the probability of NOT getting a queen is 48/49 - higher than in the previous example.
What is the probability of not getting a 7 or 11 on either of two tosses of a pair of dice?
First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.
How many possible hands are there for getting 4 cards in the same suit with the other cards in any other random suit?
The odds of getting 4 cards in any particular suit (for example, hearts) would be:1/4*1/4*1/4*1/4=1/256.The odds of getting 4 cards of the same suit (any suit) would be 4x greater:1/256*4=1/64Because it doesn't matter what the last card is, the probability is 1/64.
What is the probability of drawing two hearts from a standard pack of cards is 3 divided 51 what is the probability that the two cards drawn are not both hearts?
The probability of drawing a heart from a fair deck is 1 in 4. If the card is replaced then the probability is again 1 in 4. The probability of drawing a card other than a heart is 3 in 4. Once again if the card is replaced then the probability remains 3 in 4
