3x + 8 = 8 Therefore, 3x = 0 x = 0/3 x = 0
To find the possible values of x in the equation 6x2 + 7x - 3 = 0, you can try to factor the equation: 6x2 + 7x - 3 = 0 6x2 + 9x - 2x - 3 = 0 3x(2x + 3) - 1(2x + 3) = 0 (3x - 1)(2x + 3) = 0 Now you can solve the individual factors for zero, giving you all potential answers to the problem: 3x - 1 = 0 x = 1/3 2x + 3 = 0 x = -3/2 So the possible values of x are -3/2 and 1/3
If you mean: (3x-1)(x+1) = 0, then it is 3x squared+2x-1 = 0. Its solutions are: x = 1/3 or x = -1.
The four solution values of x of 3x4 + 7x3 + 4x2 = 0 are: x = -11/3, -1, 0 (repeated) 3x4 + 7x3 + 4x2 = 0 ⇒ x2(3x2 + 7x + 4) = 0 ⇒ x2(3x + 4)(x + 1) = 0 ⇒ x2 = 0 → x = 0 (repeated) or (3x + 4) = 0 → x = -4/3 = -11/3 or (x + 1) = 0 → x = -1
3x2-9x = 0 x(3x-9) = 0 x = 0 or x = 3
3x^0 = 3(x^0) = 3 (3x)^0 = 1
Let f(x) = 3x3 - 3x - 3 then f(-1) = -3 + 3 - 3 = -3 f(0) = 0 - 0 - 3 = -3 f(1) = 3 - 3 - 3 = -3
3x + 8 = 8 Therefore, 3x = 0 x = 0/3 x = 0
1) 3x-17=0 3x=17 x=17/3 2) 3x-25=0 3x=25 x=25/3
To find the possible values of x in the equation 6x2 + 7x - 3 = 0, you can try to factor the equation: 6x2 + 7x - 3 = 0 6x2 + 9x - 2x - 3 = 0 3x(2x + 3) - 1(2x + 3) = 0 (3x - 1)(2x + 3) = 0 Now you can solve the individual factors for zero, giving you all potential answers to the problem: 3x - 1 = 0 x = 1/3 2x + 3 = 0 x = -3/2 So the possible values of x are -3/2 and 1/3
3x = 2y + 3 3x -3 = 2y +3 -3 3x - 3 = 2y (3x -3)/2 = 2y / 2 y = 1/2 x (3x - 3) 3x = 2y +3 3x - 3x = -3x +2y +3 0 = -3x +2y +3 -1 x (0) = -1 x (-3x +2y +3) 0 = 3x - 2y -3
3x = 2y + 3 3x -3 = 2y +3 -3 3x - 3 = 2y (3x -3)/2 = 2y / 2 y = 1/2 x (3x - 3) 3x = 2y +3 3x - 3x = -3x +2y +3 0 = -3x +2y +3 -1 x (0) = -1 x (-3x +2y +3) 0 = 3x - 2y -3
If you mean: (3x-1)(x+1) = 0, then it is 3x squared+2x-1 = 0. Its solutions are: x = 1/3 or x = -1.
If you mean: 3x squared -11x -20 = 0 Then: x = -5 or x = 4/3
let f(x) = 3x^2 - 3x + 1. The roots of f is the same as asking for x where f(x) = 0. So we do it f(x) = 0, 3x^2 - 3x + 1 = 0. Using "complete the square" method 3(x^2 - x) + 1 = 0 3(x^2 + (2 . - 1/2 . x) + (-1/2)^2 -(-1/2)^2) + 1 = 0 3(x - 1/2)^2 -3/4 + 1 = 0 3(x - 1/2)^2 + 1/4 = 0 By the quadratic formula, the solution comes out to be x = [3+√(-3)]/6 and x = [3-√(-3)]/6 or x = (3+i√3)/6 and x = (3-i√3)/6 in other words, the solutions are complex numbers.
The four solution values of x of 3x4 + 7x3 + 4x2 = 0 are: x = -11/3, -1, 0 (repeated) 3x4 + 7x3 + 4x2 = 0 ⇒ x2(3x2 + 7x + 4) = 0 ⇒ x2(3x + 4)(x + 1) = 0 ⇒ x2 = 0 → x = 0 (repeated) or (3x + 4) = 0 → x = -4/3 = -11/3 or (x + 1) = 0 → x = -1
3x2-9x = 0 x(3x-9) = 0 x = 0 or x = 3