6-3x+12=0 6+12-3x=0 18-3x=0 18=3x x=6
0 - - 3x - 1 = 3x - 1
3x - 3x -1 + 2x -1 = 0 0 - 1 + 2x - 1 = 0 2x - 2 = 0 2x = 2 x = 1
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
9x2 + 18x - 16 = 0 ⇒ (3x - 2)(3x + 8) = 0 ⇒ 3x - 2 = 0 → x = 2/3 or 3x + 8 = 0 → x = -22/3
0
6-3x+12=0 6+12-3x=0 18-3x=0 18=3x x=6
0 - - 3x - 1 = 3x - 1
y = -1x/2 3x + 6y = 0 -3x -3x __________ 6y = 0 - 3x --- -------- 6 6 y= -3x/6 y= -1x/2
3x - y = -4 3x - y = 0 Those lines do not intersect. They are parallel. You can demonstrate by solving either of them for one of the two variables, then plugging it's value into the other: 3x - y = -4 ∴y = 3x + 4 Now substitute: 3x - y = 0 ∴ 3x - (3x + 4) = 0 ∴ 3x - 3x - 4 = 0 ∴ -4 = 0 This result is obviously incorrect, indicating that the lines do not intersect.
5*2-3x-1 = 0 10-3x-1 = 0 -3x = 1-10 -3x = -9 x = 3
(0, 0) of course! No linear term! Review you vertex manipulation again.
3x - 3x -1 + 2x -1 = 0 0 - 1 + 2x - 1 = 0 2x - 2 = 0 2x = 2 x = 1
3x + 2 = 0 3x = -2 x = -2/3
3x + 8 = 8 Therefore, 3x = 0 x = 0/3 x = 0
3X+70-7*18=0 3X+70-126=0 3X-56=0 3X=56 x=56/3 or 18.6667
If 3X-27= 0 then X=9