3x^0 = 3(x^0) = 3
(3x)^0 = 1
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6-3x+12=0 6+12-3x=0 18-3x=0 18=3x x=6
0 - - 3x - 1 = 3x - 1
3x - 3x -1 + 2x -1 = 0 0 - 1 + 2x - 1 = 0 2x - 2 = 0 2x = 2 x = 1
9x2 + 18x - 16 = 0 ⇒ (3x - 2)(3x + 8) = 0 ⇒ 3x - 2 = 0 → x = 2/3 or 3x + 8 = 0 → x = -22/3
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0