3x2 -12x+24=-10x-20-3x2+6
3x^2 - x + 20 = 0 doesn't factor neatly. Using the quadratic formula, we find two complex roots with imaginary solutions.(1 plus the square root of -239) divided by 6(1 minus the square root of -239) divided by 6x = 0.16666 repeating + 2.576604138956718ix = 0.16666 repeating - 2.576604138956718iwhere i is the square root of negative one.
If: y = kx+1 and y = 3x2-4x+4 Then: 3x2-4x+4 = kx+1 So: 3x2-4x-kx+3 = 0 For the line to be tangent to the curve the discriminant of b2-4ac must = 0 So when: -4*3*3 = -36 then (-4-k)2 must = 36 So it follows: (-4-k)(-4-k) = 36 => k2+8k-20 = 0 Solving the quadratic equation: k = 2 or k = -10
-- First, write the quadratic formula on the back of your hand:x = 1/2A [ -B ± sqrt(B2 - 4AC) ]-- Then, stare at your equation until it dawns on you thatA = 12B = -77C = -20-- Substitute these values of 'A', 'B', and 'C' into the quadratic formula,evaluate it for the two values of 'x', and the two solutions practicallyfall out on the floor and surrender, on their own.
They are 1*1, 2*2, 3*3 and so on, until 20*20. Use a calculator to work out the values.
(3x-4)(x+5)
If that's - 11x - 20, the answer is (4x + 5)(x - 4). If that's + 11x + 20, it gets ugly in a hurry.
3x2 - 7x - 20 = (3x + 5)(x - 4)
-11x=22011x=-220x=-220/11=-20
11x + 8 = 8x + 20 3x + 8 = 20 3x = 12 x = 4
4x2-11x-20=(x-4)(4x+5) 4x2-11x-20=4x2+ax+bx-20ab = 4*-20 = -80a+b = -11a = -16, b = 54x2-11x-20=4x2-16x+5x-204x2-16x+5x-20=4x(x-4)+5(x-4)4x(x-4)+5(x-4)=(x-4)(4x+5)Factorised, 4x2-11x-20=(x-4)(4x+5)
3x2 -12x+24=-10x-20-3x2+6
13x + 15 = 11x - 5 2x = -20 x = -10
11x = 20x +1811x-20x=18x(11-20)=18-9x=18x=-2
3x2-7x-20 = (3x+5)(x-4) when factored
x + 20 + 10x = 20 + 9x 11x + 20 = 20 + 9x Subtract 20 from both sides: 11x = 9x Subtract 9x from both sides: 2x = 0 Divide both sides by 2: x = 0
(3x + 5)(x - 4)