Q: Given three positive real numbers satisfying the triangle inequalities is it always possible to find a triangle having these as the dimensions?

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Thanks to the browser, it is not possible to tell what the inequalities are.

There are, of course, infinitely many solutions here. Choose any two positive numbers for the first two dimensions. Then divide 336 by the product of the two numbers, to get the third dimension.

In question and answer logic answers are given and if they fall in an area bounded by the inequality then it is a good answer. After graphing three or more inequalities the vertexes are the possible maxima of the system of equations.

The only dimensions possible are those specified in the question.

Yes, it is possible. Since their boundaries are parallel the relevant equations are of the form y = mx + c1 and y = mx + c2. Then if c1 > c2, the inequalities must be of the form y â‰¥ mc + c1 and y â‰¤ mx + c2

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Thanks to the browser, it is not possible to tell what the inequalities are.

yes it is possible for a system of two linear inequalities to have a single point as a solution.

The dimensions for both are Length.The dimensions for both are Length.The dimensions for both are Length.The dimensions for both are Length.

Scientists have been and are still working hard to check on different dimensions and if travelling is actually possible between dimensions.

For a rectangle, I assume. Choose any positive number for the first side; then divide 885 by that to get the second side.

There are, of course, infinitely many solutions here. Choose any two positive numbers for the first two dimensions. Then divide 336 by the product of the two numbers, to get the third dimension.

The answer depends entirely on how the dimensions change. It is possible to change the dimensions without changing the perimeter. It is also possible to change the dimensions without changing the area. (And it is possible to change the area without changing the perimeter.)

In question and answer logic answers are given and if they fall in an area bounded by the inequality then it is a good answer. After graphing three or more inequalities the vertexes are the possible maxima of the system of equations.

180 is a pure number and has no dimensions.

to make as much profit as possible, satisfying their customers with outstanding products.

The only dimensions possible are those specified in the question.

Yes, it is possible. Since their boundaries are parallel the relevant equations are of the form y = mx + c1 and y = mx + c2. Then if c1 > c2, the inequalities must be of the form y â‰¥ mc + c1 and y â‰¤ mx + c2