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What point is a solution to this linear quadratic system yx2 plus 4x plus 3 and y2x plus 6?
If you mean: y = x^2+4x+3 and y = 2x+6 Then the solution is: x = 1 or x = -3
What is the solution of the system for yx 6 y2x?
Without a second independent equation, it's not a 'system' yet.
Is y2x plus 5 linear equation?
If you mean: y = 2x+5 then it is a straight line equation.
What is the solution set to the inequality y2x-8?
10
How can a graph for the rule y2x plus 1 be used to predict the result for an input of 7?
The y value will equal 15, when x = 7
What point is a solution to this linear quadratic system yx2 plus 4x plus 3 and y2x plus 6?
If you mean: y = x^2+4x+3 and y = 2x+6 Then the solution is: x = 1 or x = -3
What is y2x plus 9?
It is an expression in two variables, x and y.
What is the solution of the system for yx 6 y2x?
Without a second independent equation, it's not a 'system' yet.
Is y2x plus 5 linear equation?
If you mean: y = 2x+5 then it is a straight line equation.
What is the solution of y2x and x 2y5 using substitution?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (eg x-squared = x^2). Neither y2x nor x 2y5 is an equation.
What is the solution set to the inequality y2x-8?
10
What is y6x plus 11 y2x plus 7 in substitution method?
If you mean: y = 6x+11 and y = 2x+7 Then by substitution: x = -1 and y = 5
What solution is y2x-1 and 3y6x-5?
Without any equality signs the given expressions can't be considered to be equations so therefore there are no solutions.
What is the answer to y x plus 2 y2x-5?
Since there is no equality (or inequality) sign in the question, there is no equation or inequality) and therefore nothing which can be solved.
How can a graph for the rule y2x plus 1 be used to predict the result for an input of 7?
The y value will equal 15, when x = 7
Solve the system of liner equation by graphing 2x plus y1and y2x plus 1?
Without any equality signs the given expression can't be considered to be straight line equations.
What is a solution for the system of equations x-y2 and y2x-4?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.
