Assuming that the length is at least as great as the width, the length can have any value, L, between 25 and 50 feet.
The width, W, then would be 50 - L feet.
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
Length + length + width + width = perimeter. Length + width x 2 = perimeter
width = (perimeter-2*length)/2
Perimeter = 2 lengths + 2 widths 1/2 perimeter = length + width Length = 1/2 perimeter - width Area = length x width That's (1/2 perimeter - width) x (width) .
Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length
The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
Because the perimeter is lenght + length +width +width, you do perimeter - double the width, and then halve the remaining number. that should give you the length.
Perimeter = length + length + width + width Let "w" = width, then "7w" must equal the length (because it's 7 times the width) 7w + 7w + w + w = perimeter 16w = perimeter
The perimeter is the total distance around - width + width+ length + length.
you need length and width length multiply width = area length + length + width + width = perimeter