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Let the two integers be x and y, and y > x. So that,

(x + y)/(y - x) = 11/5 (multiply both sides by y - x)

x + y = (11/5)(y - x)

x + y = 11y/5 - 11x/5 (add (11x/5 and subtract y to both sides)

x + 11x/5 = 11y/5 - y (multiply each term in both sides by 5)

5x + 11x = 11y - 5y

16x = 6y (divide by 6 to both sides)

(16/6)x = y

(8/3)x = y

(x + y) - (y - x) = 24

x + y - y + x = 24

2x = 24 (divide by 2 to both sides)

x = 12

(8/3)x = y (substitute 12 for x)

(8/3)(12) = y

(8)(4) = y

32 = y

Thus, xy = (12)(32) = 384

Q: Help please The ratio of the sum and difference of two positive integers is 11 divided by 5 if the difference between the sum and difference is 24 what is the product of the two integers?

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