a0=(a-1\a-1)=a\a=1
16 pages of A4 fit into an A0
f(x) = a0 + a1x + a2x2 + a3x3 + ... + anxn for some integer n, and constants a0, a1, ... an.
Time
4
A0
A0 paper is 46.8 x 33.1 in.
a0=(a-1\a-1)=a\a=1
For an exponential function: General equation of exponential decay is A(t)=A0e^-at The definition of a half-life is A(t)/A0=0.5, therefore: 0.5 = e^-at ln(0.5)=-at t= -ln(0.5)/a For exponential growth: A(t)=A0e^at Find out an expression to relate A(t) and A0 and you solve as above
A= A0e^-kt A0= A/ e^kt = Ae^kt A0= A+ D* D*= A0- A D*= Ae^kt - A D*= A(e^kt - 1)
16 pages of A4 fit into an A0
Suppose the sequence is defined by an = a0 + n*d Then a1 = a0 + d = 15 and a13 = a0 + 13d = -57 Subtracting the first from the second: 12d = -72 so that d = -6 and then a0 - 6 = 15 gives a0 = 21 So a32 = 21 - 32*6 = -171
In the standardised paper measurement system A0 is 1189 millimetres x 841 millimetres.
yes
f(x) = a0 + a1x + a2x2 + a3x3 + ... + anxn for some integer n, and constants a0, a1, ... an.
A0 is 1 meter square.
A = A0 e-Bt