110 ft x 16 ft = 110*0.3048 metres x 16*0.3048 metres = 163.5 sq metres (approx).
Two pavers of 16 ft x 16 ft will be sufficient.
If you mean 16 ft x 16 ft then 2 tiles will suffice. If you did not mean 16 ft x 16 ft you could have considered mentioning what units of measurement you meant.
Two tiles of 16 ft*16 ft will cover 512 square feet.
80 ft x 110 ft = 0.202020... acres
110 ft x 16 ft = 110*0.3048 metres x 16*0.3048 metres = 163.5 sq metres (approx).
Convert the inches to feet and work out the volume of the cuboid with base area 110 sq ft and height of 3 inches: 12 in = 1 ft → volume = 110 sq ft x 3 in = 110 sq ft x 3/12 ft = 27 ½ cu ft (= 27.5 cu ft)
it will take 1.33 2x6s to cover 16 feet.
Two pavers of 16 ft x 16 ft will be sufficient.
If you mean 16 ft x 16 ft then 2 tiles will suffice. If you did not mean 16 ft x 16 ft you could have considered mentioning what units of measurement you meant.
Two tiles of 16 ft*16 ft will cover 512 square feet.
80 ft x 110 ft = 0.202020... acres
like 110=-120
95-110 lbs :)
13 X 16 divided by 9 = 23.11 square yards
12 in = 1 ft volume = area × depth = 16 sq ft × 2 in = 16 sq ft × (2 ÷ 12) ft = 2⅔ cu ft ≈ 2.67 cu ft
Given: s0 = 2 ft and v0 = 110 ft/sec. The ball is under the influence of gravity, so the acceleration of gravity, g = 32 ft/sec2. The height of the ball (in feet) after t seconds is given by s(t) = -(1/2)gt2 + v0t + s0. So we have: s(t) = -16t2 + 110t + 2 (a parabola which opens downward, so its vertex is a max. point) Thus, t = -(110)/(2*-16) = 55/16, and s(55/16) = -16(55/16)2 + 110(55/16) + 2 = -1*552/16 + 2*55*55/16 + 32/16 = [552(2 - 1) + 32]/16 = (3025 + 32)/16 = 3057/16 ≈ 191 ft