To determine how many 1x6 boards, each 16 feet long, are needed to cover 110 square feet, first calculate the area of one board. A 1x6 board is actually 0.75 inches thick by 5.5 inches wide, which converts to 0.0625 feet by 0.4583 feet. The area of one board is approximately 0.0287 square feet. Dividing 110 square feet by this area gives you about 3,833 boards, but since each board is 16 feet long and covers more area, you should calculate using the total coverage of each board properly. You’d actually need around 12 boards to cover that area, considering the actual dimensions.
110 ft x 16 ft = 110*0.3048 metres x 16*0.3048 metres = 163.5 sq metres (approx).
To determine how many 1x6x16 ft T&G boards you need to cover 801 square feet, first calculate the area covered by one board. A 1x6 board is approximately 0.5 ft wide and 16 ft long, so it covers about 8 square feet (0.5 ft x 16 ft). Dividing 801 square feet by 8 square feet per board gives you approximately 100.125 boards. Therefore, you would need 101 boards to cover the area, accounting for any waste or cuts.
Two pavers of 16 ft x 16 ft will be sufficient.
If you mean 16 ft x 16 ft then 2 tiles will suffice. If you did not mean 16 ft x 16 ft you could have considered mentioning what units of measurement you meant.
Two tiles of 16 ft*16 ft will cover 512 square feet.
110 ft x 16 ft = 110*0.3048 metres x 16*0.3048 metres = 163.5 sq metres (approx).
Convert the inches to feet and work out the volume of the cuboid with base area 110 sq ft and height of 3 inches: 12 in = 1 ft → volume = 110 sq ft x 3 in = 110 sq ft x 3/12 ft = 27 ½ cu ft (= 27.5 cu ft)
it will take 1.33 2x6s to cover 16 feet.
Two pavers of 16 ft x 16 ft will be sufficient.
If you mean 16 ft x 16 ft then 2 tiles will suffice. If you did not mean 16 ft x 16 ft you could have considered mentioning what units of measurement you meant.
Two tiles of 16 ft*16 ft will cover 512 square feet.
80 ft x 110 ft = 0.202020... acres
like 110=-120
95-110 lbs :)
13 X 16 divided by 9 = 23.11 square yards
12 in = 1 ft volume = area × depth = 16 sq ft × 2 in = 16 sq ft × (2 ÷ 12) ft = 2⅔ cu ft ≈ 2.67 cu ft
Given: s0 = 2 ft and v0 = 110 ft/sec. The ball is under the influence of gravity, so the acceleration of gravity, g = 32 ft/sec2. The height of the ball (in feet) after t seconds is given by s(t) = -(1/2)gt2 + v0t + s0. So we have: s(t) = -16t2 + 110t + 2 (a parabola which opens downward, so its vertex is a max. point) Thus, t = -(110)/(2*-16) = 55/16, and s(55/16) = -16(55/16)2 + 110(55/16) + 2 = -1*552/16 + 2*55*55/16 + 32/16 = [552(2 - 1) + 32]/16 = (3025 + 32)/16 = 3057/16 ≈ 191 ft