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How much width and length in 193sqft?
There are infinitely many possible answers. Let L = any length greater than or equal to sqrt(193) feet. and let W = 193/L then any rectangle with length L and width W has an area of L*W = L*(193/L = 193 sq feet. And since L can have an infinite number of values, there are infinitely many solutions. Furthermore, this is just for rectangular shapes. The area could be circular, triangular or any other shape.
What does the l mean in survival?
it doenst have any specific meanin.
What are the dimension of a rectangle with 60 square units?
The area of a rectangle does not provide enough information. Let L be any number greater than sqrt(60) = approx 7.75 and let B = 60/L. Then a rectangle with length L units and Breadth B units will have an area of L*B = L*(60/L) = 60 square units. Since L can be any number greater than 7.75, there are infiitely many choices for L and so infinitely many possible rectangles.
What is the L x W x H to get 1412 cubic feet?
Several combinations are possible. Use any number for L and for W, then divide 1412 / (L x W) to get the third number.
What is the length and width size of 500 sqft?
There is not enough information to answer the question. First of all, the shape of the area is unknown. Even if it were a rectangle, all that can be said is that one of the sides must be at least sqrt(500) = 22.36 ft (approx). Take any number L greater than 22.36 and let W = 500/L Consider a rectangle with Length = L ft and Width = W ft. The area of such a rectangle is L*W = L*(500/L) = 55 sq ft. But L is ANY length more than 22.36 feet. There are infinitely many possible values for L.
