Points: (-1, 2) and (3, 3) Slope: 1/4
Slope = (1 - 4)/(3 - 1) = -3/2 = -1.5
-1
If you mean coordinates of (-3, 67) and (2, -14) then it works out as 81.154 rounded to 3 d.p.
{(5, 2), (3, 4), (1, 2), (−1, 4)}
Points: (-1, 2) and (3, 3) Slope: 1/4
Points: (-3, -1) and (3, -2) Slope: -1/6
Slope = (1 - 4)/(3 - 1) = -3/2 = -1.5
-1
If you mean coordinates of (-3, 67) and (2, -14) then it works out as 81.154 rounded to 3 d.p.
Its center is at (-1, 1/2)
If you mean the coordinates of the line x-y = 2 that intersects the curve of x2-4y2 = 5 Then the coordinates work out as: (3, 1) and (7/3, 1/3)
{(5, 2), (3, 4), (1, 2), (−1, 4)}
The point whose Cartesian coordinates are (-3, -3) has the polar coordinates R = 3 sqrt(2), Θ = -0.75pi.
Not too sure of the question but if A is (1, 2) and B is (-3, -1) then it is a right angle triangle if the coordinates of C are at (1, -1) or (-3, 2)
Points: (-14, 3) and (2, -5) Slope: -1/2
What are polar coordinates of (√2, 1)? Solution: Here we need to convert from rectangular coordinates to polar coordinates: P = (x, y) = (r, θ) r = ± √(x^2 + y^2); tan θ = y/x or θ = arc tan (y/x) So we have: P = (√2, 1) r = ± √[(√2)^2 + 1^2] = ± √3 θ = arc tan (y/x) = arc tan (1/√2) = arc tan (√2/2) ≈ 35.3°, which is one possible value of the angle. (√2, 1) is in the Quadrant I. If θ = 35.3°, then the point is in the terminal ray, and so r = √3. Therefore polar coordinates are (√3, 35.3°). Another possible pair of polar coordinates of the same point is (-√3, 215.3°) (180° + 35.3° = 215.3°). Edit: Note the negative in the r value.