Points: (-3, 2) and (7, 6) Slope: 2/5 Equation: 5y-2x = 16 x intercept: (-8, 0)
The coordinates will be at the point of the turn the parabola which is its vertex.
no
The midpoint formula is: [(x1 + x2)/2, (y1 + y2)/2]. If we denote the coordinates of the point C as (x1, y1) = (2, 6), and the coordinates of the point D as (x2, y2) = (4, 0), we can find the coordinates of the midpoint by using the above formula. So, [(x1 + x2)/2, (y1 + y2)/2] = [(2 + 4)/2, (6 + 0)/2] = (3, 3)
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
What are polar coordinates of (√2, 1)? Solution: Here we need to convert from rectangular coordinates to polar coordinates: P = (x, y) = (r, θ) r = ± √(x^2 + y^2); tan θ = y/x or θ = arc tan (y/x) So we have: P = (√2, 1) r = ± √[(√2)^2 + 1^2] = ± √3 θ = arc tan (y/x) = arc tan (1/√2) = arc tan (√2/2) ≈ 35.3°, which is one possible value of the angle. (√2, 1) is in the Quadrant I. If θ = 35.3°, then the point is in the terminal ray, and so r = √3. Therefore polar coordinates are (√3, 35.3°). Another possible pair of polar coordinates of the same point is (-√3, 215.3°) (180° + 35.3° = 215.3°). Edit: Note the negative in the r value.
(4,-3)
Degrees, radians, or polar coordinates. (3 ways)
4875893948
(-3,-3)
You do not have 3 coordinates in the Cartesian plane. The Cartesian plane is a plane and is therefore 2 dimensional. In 2 dimensional space you require only 2 coordinates. 3 coordinates are required to locate a point in 3-dimensional space but then it cannot be a Cartesian PLANE.
-1
The coordinates of point B can be calculated using the midpoint formula. The midpoint formula is used to find the midpoint of two points, and is calculated by taking the average of the x-coordinates and the average of the y-coordinates. In this case, we are given the midpoint of AB, which is (-2, -4). We also know the coordinates of point A, which are (-3, -5). Using the midpoint formula, we can calculate the x-coordinate of point B by taking the average of the x-coordinates of points A and M. This is (-3 + -2)/2 = -2.5. We can calculate the y-coordinate of point B in a similar way. This is (-5 + -4)/2 = -4.5. Therefore, the coordinates of point B are (-2.5, -4.5).
Points: (-3, 2) and (7, 6) Slope: 2/5 Equation: 5y-2x = 16 x intercept: (-8, 0)
The new coordinates are(3 + the old 'x', 2 + the old 'y')
A point has coordinates (-3, 0). Where is it located in the coordinate plan?A point has coordinates (-3, 0). Where is it located in the coordinate plan?
-2