The integerst that equal 5 are related because their sum will always result in 5, regardless of their order.
The (not th) definition (not defition) of opposite integers are integers that are equal in their [absolute] value but have different signs. So, for example, the opposite of +4 is -4, and the opposite of -5 is +5.
The absolute values of opposite integers are always equal. For example, the absolute value of -5 is 5, and the absolute value of 5 is also 5. This relationship holds true for any pair of opposite integers, as absolute value measures the distance from zero on the number line, disregarding direction. Thus, regardless of their signs, the absolute values remain the same.
-5, -4, -3, -2, -1, 0 , 1, 2, ...
-(x-5) When you take the integers out right behind the "-" is a 1. so when you expand it will equal -x+5
Five of them.
The (not th) definition (not defition) of opposite integers are integers that are equal in their [absolute] value but have different signs. So, for example, the opposite of +4 is -4, and the opposite of -5 is +5.
The absolute values of opposite integers are always equal. For example, the absolute value of -5 is 5, and the absolute value of 5 is also 5. This relationship holds true for any pair of opposite integers, as absolute value measures the distance from zero on the number line, disregarding direction. Thus, regardless of their signs, the absolute values remain the same.
-1, -3, -5
-5, -4, -3, -2, -1, 0 , 1, 2, ...
-(x-5) When you take the integers out right behind the "-" is a 1. so when you expand it will equal -x+5
Five of them.
To determine which integers will make ( x = 5 ), we set ( x ) equal to 5 directly. Thus, the only integer that will satisfy this condition is 5 itself. Any equation or expression that leads to ( x = 5 ) will also yield this integer as the solution.
To find how many positive integers less than or equal to 10,000 are divisible by 2, 5, or 10, we can use the principle of inclusion-exclusion. The count of integers divisible by each is: Divisible by 2: ( \frac{10000}{2} = 5000 ) Divisible by 5: ( \frac{10000}{5} = 2000 ) Divisible by 10: ( \frac{10000}{10} = 1000 ) Applying inclusion-exclusion, we have: [ 5000 + 2000 - 1000 = 6000 ] Thus, there are 6000 positive integers less than or equal to 10,000 that are divisible by 2, 5, or 10.
The sum of two positive integers can never equal zero.
There are two consecutive even integers that equal -298: -150 and -148.
The integers are 106 and 108.
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