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The numbers are 62 and 64 are two consecutive integers that equal 126.

Q: What are two consecutive even integers that equal 126?

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There is no solution. Since 126 is even and two consecutive integers have to be one odd and one even number, an odd and an even number cannot summate to an even number.

The numbers are 62 and 64.

41,42,43

The integers are are 41, 42 and 43.

:/ We can write it this way: x - 1 + x + x + 1 = 126. 1s cancel out, so we get 3x = 126. 126/3 = 42. Answer: 41, 42, 43.

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The two even consecutive integers are: 62+64 = 126

There is no solution. Since 126 is even and two consecutive integers have to be one odd and one even number, an odd and an even number cannot summate to an even number.

63+83=126.... hope it helps!

The numbers are 62 and 64.

Divide 126 by 2 and choose the even numbers on both sides.

41,42,43

41+42+43=126.

Let the intgers be n- 1 n , & n+1 . This is consecutive. Hence Adding (n-1) + n + ( n +1) = 126 Add the LHS 3n = 126 Divide both sides by '3' n = 42 Hence n- 1 = 41 & n +1 = 43 So the consecutive integers are 41,42, & 43.

The integers are are 41, 42 and 43.

The numbers are 125 and 126.

41, 42 and 43

:/ We can write it this way: x - 1 + x + x + 1 = 126. 1s cancel out, so we get 3x = 126. 126/3 = 42. Answer: 41, 42, 43.