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Condsider the sequence of 1s.

And let Sn be the sum of the first n terms.

Then S1 = 1, S2 = 2, S3 = 3 and so on. As the number of terms becomes larger so does the corresponding S. As n tends to infinity, so does Sn.

A "proper" proof would be to show that if you give me any number X (however large), I can find a number k such that Sn is greater than X for all n greater than k.

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