In a parabola defined by the equation ( y = ax^2 + q ), the parameter ( a ) determines the direction and width of the parabola, while ( q ) represents the vertical shift. To solve the effect of ( a ), consider its value: if ( a > 0 ), the parabola opens upward and is narrower as ( |a| ) increases; if ( a < 0 ), it opens downward and becomes wider as ( |a| ) decreases. The parameter ( q ) shifts the entire parabola up or down by ( q ) units without altering its shape. Adjusting these parameters allows for a comprehensive understanding of the parabola's position and orientation in the coordinate plane.
what are the effects of the sign a and n to the parabola
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
No you can't. There is no unique solution for 'x' and 'y'. The equation describes a parabola, and every point on the parabola satisfies the equation.
q = 78
The standard form of the equation of a parabola that opens up or down is given by ( y = a(x - h)^2 + k ), where ( (h, k) ) is the vertex of the parabola and ( a ) determines the direction and width of the parabola. If ( a > 0 ), the parabola opens upward, while if ( a < 0 ), it opens downward. The vertex form emphasizes the vertex's position and the effect of the coefficient ( a ) on the parabola's shape.
what are the effects of the sign a and n to the parabola
Today we'll study the parabola effect.
A parabola is a graph of a 2nd degree polynomial function. Two graph a parabola, you must factor the polynomial equation and solve for the roots and the vertex. If factoring doesn't work, use the quadratic equation.
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
Set y = 0 and solve for x, with a parabola you should get one, two, or no x-axis crossings, it depends on the equation and the location on the x-y axis of the parabola.
No you can't. There is no unique solution for 'x' and 'y'. The equation describes a parabola, and every point on the parabola satisfies the equation.
If you know the equation, you just plug in x = 0 and solve.
q = 78
By factoring. q2 + 16q = 0 q (q + 16) = 0 Now, either q = 0, or q + 16 = 0. Solve those two equations to get the solution.
3q = 18 q = 6
The focus of a parabola is a fixed point that lies on the axis of the parabola "p" units from the vertex. It can be found by the parabola equations in standard form: (x-h)^2=4p(y-k) or (y-k)^2=4p(x-h) depending on the shape of the parabola. The vertex is defined by (h,k). Solve for p and count that many units from the vertex in the direction away from the directrix. (your focus should be inside the curve of your parabola)
q=4k+4uImproved Answer:-If: Q = 4k+4uThen: k = (4u-Q)/-4