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3q = 18

q = 6

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Q: How do you solve 3q - 5 13 for q.?
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Solve -3q plus 4 equals 6q equals 13?

If -3q + 4 = 13 then 3q = -9 : q = -3 If 6q = 13 then q = 13/6 = 2 1/6 The question contains an anomaly and is invalid.


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2p + 3q = 13, 5p - 4q = -2 Multiply the first equation by 4 and the second by 3 and add them, which gets rid of the q: 8p + 15p = 52 - 6, and 23p = 46, so p=2. Plug that into the first equation to find q: 4 + 3q = 13, so q=3. Test your answers in the second equation to be sure: 5(2) - 4(3) = 10-12 = -2. It checks. So p=2, q=3.


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30q3 + 14q2 - 4q = 0 can be factored as q(30q2 + 14q - 4) = 0 The bracketed term can be factored (30q2 + 14q - 4) = (10q - 2)(3q + 2) The equation can now be written : q(10q - 2)(3q + 2) = 0 The equation = 0 when either q = 0 or one of the bracketed terms = 0 When 10q - 2 = 0 then q = 2/10 = 1/5 : and when 3q + 2 = 0 then q = -2/3.