You can use four 7s to make 56 by applying mathematical operations. One way to achieve this is: ( (7 \times 7) + (7 \div 7) = 49 + 1 = 50 ), which does not directly work. Instead, you can also express it as ( 7 \times (7 + 7) \div 7 = 56 ). However, a correct and straightforward solution is simply ( 7 \times 8 = 56 ).
-8 x 7/12 = -56/12 or -4 and 2/3
You said that 4(2s - 1) = 7s + 12Eliminate parentheses: 8s - 4 = 7s + 12Add 4 to each side: 8s = 7s + 16Subtract 7s from each side: s = 16
-1, - 1 , -1 and -56. When multiplied together, they make +56.
4
Bring all the unknown values to one side and the known values to the other 7s - 12 = 3s - 4 Subtract 3s from both sides 7s - 3s - 12 = 4 4s - 12 = 4 Add 12 to both sides 4s = 4 + 12 4s = 16 Divide both sides by 4 s = 4
-8 x 7/12 = -56/12 or -4 and 2/3
You said that 4(2s - 1) = 7s + 12Eliminate parentheses: 8s - 4 = 7s + 12Add 4 to each side: 8s = 7s + 16Subtract 7s from each side: s = 16
answer:4
-1, - 1 , -1 and -56. When multiplied together, they make +56.
77 / 7 - 777 / 7 - 777 / 7 - 777 / 7 - 7
1 * 56 = 56 2 * 28 = 56 4 * 14 = 56 7 * 8 = 56 8 * 7 = 56 14 * 4 = 56 28 * 2 = 56 56 * 1 = 56
4
If you mean: 4(2s-1) = 7s+12 then the value of s works out as 16
Bring all the unknown values to one side and the known values to the other 7s - 12 = 3s - 4 Subtract 3s from both sides 7s - 3s - 12 = 4 4s - 12 = 4 Add 12 to both sides 4s = 4 + 12 4s = 16 Divide both sides by 4 s = 4
Oh, dude, you just gotta think outside the box. Like, take one of the fives and cut it in half diagonally, then attach the top half to the other five to make an "S." Now you have a 56! Easy peasy, right?
Oh, what a lovely little math puzzle we have here! Let's see, to find the 4 numbers that multiply together to make 56, we can start by thinking about factors of 56. How about 1, 2, 4, and 14? When you multiply these numbers together, you get 56. Isn't that just delightful? Remember, there are many ways to approach a problem, and it's all about enjoying the process of discovery.
4 times with a remainder of 3