Perimeter = 4 times the square root of the area.
It is: perimeter minus hypotenus+base = height Area = 0.5*base*height
You multiply the base and the height and then you divide the answers of that by 2. :)
all you have to do is add together the four sides. 2L+2W=Perimeter (L=length or base, W=Width or height)
In that case, it would be good to know WHAT is given. If NOTHING is given, you really can't calculate.
Height = (Perimeter/2) - Base
If you are given the width and the perimeter, then figure out what the length is then calculate the area... hope this helps :)
Perimeter = 4 times the square root of the area.
It is: perimeter minus hypotenus+base = height Area = 0.5*base*height
Please clarify what data is given, and what you want to solve for. To calculate the perimeter, add the length of all four sides. To calculate the area, the formula is basically same as for a rectangle: length x height; however, the height must be measured perpendicular to the side which you use as "length".
You multiply the base and the height and then you divide the answers of that by 2. :)
all you have to do is add together the four sides. 2L+2W=Perimeter (L=length or base, W=Width or height)
Multiply the height by the width
In that case, it would be good to know WHAT is given. If NOTHING is given, you really can't calculate.
The height and longer diagonal do not provide enough information to calculate the sides.
Let's denote the perimeter of the first triangle as P. Since the triangles are congruent, the perimeter of the second triangle is also P. The sum of their perimeters is then 2P. According to the given statement, this sum is three times the perimeter of the first triangle. So we have the equation 2P = 3P. Simplifying, we find that P = 0, which is not a valid solution. Therefore, there is no triangle for which the sum of the perimeters of two congruent triangles is three times the perimeter of the first triangle.
You cannot. You require more information.