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How are ordered pairs and ratios similar?
You can write ordered pairs as ratios to determine if two sets of ordered pairs form a linear or non-linear relationship. In a table of x,y values, the ordered pairs are listed as the x value first, then the corresponding y value. Remove from the table and write as a ratio of x over y, (or y over x, if you like). In a linear relationship, all the ratios of x over y, (or y over x) are equivalent.
How can you identify a linear non proportional relationship from a table a graph and an equation?
It is a relationship in which changes in one variable are accompanied by changes of a constant amount in the other variable and that the variables are not both zero.In terms of an equation, it requires y = ax + b where a and b are both non-zero.
How do you find the rule in a linear table of values?
First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.So, given that there at at least two sets of data, suppose they are as follows:x1 gets mapped to y1andx2 gets mapped to y2Then calculate m = (y2-y1)/(x2-x1)and c = y - mx for any x-y combination from the table.The rule is y = mx + c.First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.So, given that there at at least two sets of data, suppose they are as follows:x1 gets mapped to y1andx2 gets mapped to y2Then calculate m = (y2-y1)/(x2-x1)and c = y - mx for any x-y combination from the table.The rule is y = mx + c.First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.So, given that there at at least two sets of data, suppose they are as follows:x1 gets mapped to y1andx2 gets mapped to y2Then calculate m = (y2-y1)/(x2-x1)and c = y - mx for any x-y combination from the table.The rule is y = mx + c.First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.So, given that there at at least two sets of data, suppose they are as follows:x1 gets mapped to y1andx2 gets mapped to y2Then calculate m = (y2-y1)/(x2-x1)and c = y - mx for any x-y combination from the table.The rule is y = mx + c.
Is a x and y table linear?
Not necessarily.
How do you use a table of data to check whether the relationship between two variables is a direct variation?
if it passes through (0,0) then it is a direct variation
