The table has a pattern to it!
To determine if a relationship is linear from a table, check if the differences in the y-values (output) corresponding to equal differences in the x-values (input) are constant. For a graph, a linear relationship will appear as a straight line. In an equation, if the equation can be expressed in the form (y = mx + b), where (m) and (b) are constants, it indicates a linear relationship.
A table represents a linear relationship if the change in the dependent variable (y) is consistent with a proportional change in the independent variable (x). This can be confirmed by calculating the slope between consecutive points; if the slope remains constant, the relationship is linear. Additionally, plotting the points on a graph should yield a straight line if the relationship is indeed linear.
To find the slope of a linear relationship from a table, select two points (x₁, y₁) and (x₂, y₂) from the table. The slope (m) can be calculated using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). To determine the y-intercept (b), substitute the slope and one of the points into the linear equation ( y = mx + b ) and solve for b. This will give you the equation of the line in the form ( y = mx + b ).
To derive an equation from a table, first identify the relationship between the variables by observing how the values change. If the relationship appears linear, calculate the slope using two points from the table and find the y-intercept. For non-linear relationships, you might need to use polynomial regression or other fitting techniques. Finally, formulate the equation based on the identified pattern or function type.
First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.So, given that there at at least two sets of data, suppose they are as follows:x1 gets mapped to y1andx2 gets mapped to y2Then calculate m = (y2-y1)/(x2-x1)and c = y - mx for any x-y combination from the table.The rule is y = mx + c.First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.So, given that there at at least two sets of data, suppose they are as follows:x1 gets mapped to y1andx2 gets mapped to y2Then calculate m = (y2-y1)/(x2-x1)and c = y - mx for any x-y combination from the table.The rule is y = mx + c.First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.So, given that there at at least two sets of data, suppose they are as follows:x1 gets mapped to y1andx2 gets mapped to y2Then calculate m = (y2-y1)/(x2-x1)and c = y - mx for any x-y combination from the table.The rule is y = mx + c.First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.So, given that there at at least two sets of data, suppose they are as follows:x1 gets mapped to y1andx2 gets mapped to y2Then calculate m = (y2-y1)/(x2-x1)and c = y - mx for any x-y combination from the table.The rule is y = mx + c.
To determine if a relationship is linear from a table, check if the differences in the y-values (output) corresponding to equal differences in the x-values (input) are constant. For a graph, a linear relationship will appear as a straight line. In an equation, if the equation can be expressed in the form (y = mx + b), where (m) and (b) are constants, it indicates a linear relationship.
you put in what x is and solve it for y! thats the answer!
To find the slope of a linear relationship from a table, select two points (x₁, y₁) and (x₂, y₂) from the table. The slope (m) can be calculated using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). To determine the y-intercept (b), substitute the slope and one of the points into the linear equation ( y = mx + b ) and solve for b. This will give you the equation of the line in the form ( y = mx + b ).
If the ratio between each pair of values is the same then the relationship is proportional. If even one of the ratios is different then it is not proportional.
If the figures in the table are exact and without measurement error then take any two of the points (x1, y1) and (x2, y2) and use these to form the linear relation y - y1 = ((y2 - y1)/(x2 - x1))(x - x1) If, however, you suspect that the values in the table do not exactly follow a linear relationship then use linear regression for which formulae are provided in wikipedia.
For a linear I can see no advantage in the table method.
All the elements are arranged according to atomic number.Number of electrons decide the position of the element.Atomic number is the root main cause of periodic table.
First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.So, given that there at at least two sets of data, suppose they are as follows:x1 gets mapped to y1andx2 gets mapped to y2Then calculate m = (y2-y1)/(x2-x1)and c = y - mx for any x-y combination from the table.The rule is y = mx + c.First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.So, given that there at at least two sets of data, suppose they are as follows:x1 gets mapped to y1andx2 gets mapped to y2Then calculate m = (y2-y1)/(x2-x1)and c = y - mx for any x-y combination from the table.The rule is y = mx + c.First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.So, given that there at at least two sets of data, suppose they are as follows:x1 gets mapped to y1andx2 gets mapped to y2Then calculate m = (y2-y1)/(x2-x1)and c = y - mx for any x-y combination from the table.The rule is y = mx + c.First assume that the relationship is linear rather than the table. If the table is linear but the relationship is non-linear it is a very different and very difficult task. Suppose, next, that you have two sets of values: inputs (x) and outputs (y). Also, you must have at least two rows of data for different inputs.So, given that there at at least two sets of data, suppose they are as follows:x1 gets mapped to y1andx2 gets mapped to y2Then calculate m = (y2-y1)/(x2-x1)and c = y - mx for any x-y combination from the table.The rule is y = mx + c.
You can write ordered pairs as ratios to determine if two sets of ordered pairs form a linear or non-linear relationship. In a table of x,y values, the ordered pairs are listed as the x value first, then the corresponding y value. Remove from the table and write as a ratio of x over y, (or y over x, if you like). In a linear relationship, all the ratios of x over y, (or y over x) are equivalent.
It is a relationship in which changes in one variable are accompanied by changes of a constant amount in the other variable and that the variables are not both zero.In terms of an equation, it requires y = ax + b where a and b are both non-zero.
A linear function can be represented in a table by listing pairs of input (x) and output (y) values that satisfy the linear equation, typically in the form y = mx + b, where m is the slope and b is the y-intercept. Each row in the table corresponds to a specific x-value, with its corresponding y-value calculated using the linear equation. As the x-values increase or decrease, the y-values will change linearly, reflecting a constant rate of change. This results in a straight-line relationship when graphed.
Not necessarily.