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How do you get 53 using only 4 fours?
4 factorial plus 4 factorial plus the square root of 4 divided by .4
Program to find n th fabonacci number?
#include #include using std::cin;using std::cout;using std::endl;using std::tolower;long factorial(const int& N);int main(){int N = 0; //factorial of Nchar command = 'n';do{cout > N;cout
Program for finding the factorial of the two given number using constructor?
kjhk
By using call by reference find the factorial of a number?
chutia mc,bc bhosdika
How do you count the vowels in a string using PHP?
build an array of vowels then do a foreach on the array and then explode the string on the array value and the answer is -1 of the result
Why and is not using ' and ' in reading a string using scanf?
I guess you wanted to ask, why is it scanf ("%s", array)and not scanf ("%s", &array).Well, array is by definition a pointer to the first element: array = &array[0]
How can you access an array without using the suffix operator?
An array's name implicitly converts to a pointer to the first element of the array at the slightest provocation. Thus to access the first element of the array, the array name suffices. To access any other element in the array without using the suffix operator, use offset pointer arithmetic. For example: int a[] = {2, 4, 6, 8, 10}; int b; b = *(a+3); assert (b == 8); Here, (a+3) points to the 4th element (offset 3). Dereferencing this address returns the value of that element, in this case 8.
Searching array element by using pointer in c plus plus?
The name of an array can be looked as a pointer of this array,and it points to the local memory address of the first element.So we can gave the address to a pointer.The flow is an easy example to show hou to use a pointer to print an array.#include "iostream.h"void main(){char a[]="abcdefgh";char *b=a;//afor(int i=0;i
Why pointer is used to reference a string of characters write C plus plus statements that display the text hello using pointer to a string notation?
We use a pointer to reference a string because a string is an array of characters where every element is a char (or a wchar_t if using UNICODE strings). Passing arrays by value would require the entire array to be copied, but passing a pointer variable to an array only copies the pointer, which is effectively the same as passing the array by reference. #include <iostream> int main() { char * psz = "hello"; // pointer to a null-terminated string. std::cout << psz; // pass the pointer (by value) to the insertion operator. return( 0 ); }
Does mentioning the array name gives the base address in all the contexts?
Mentioning the array name in C or C++ gives the base address in all contexts except one. Syntactically, the compiler treats the array name as a pointer to the first element. You can reference elements using array syntax, a[n], or using pointer syntax, *(a+n), and you can even mix the usages within an expression. When you pass an array name as a function argument, you are passing the "value of the pointer", which means that you are implicitly passing the array by reference, even though all parameters in functions are "call by value". There is, however, one very important distinction. While an array name is referentially the same as a pointer, it is not a pointer in that it does not occupy program referential space in the process. This means that, while you can change the value of a pointer, and thus the address to which it points, you can not change the value of an array name. This distinction is what we call R-Value (array or pointer) as opposed to L-Value (pointer only), i.e. can the object appear on the left sign of an assignment operator.
How do you find particular element in array?
by using index position we can find the particular element in array.
What is the relationship between an array and a pointer?
All variable names are an alias for the value stored at the memory address allocated to them. To get the memory address itself, you must use the address of operator (&). The value returned from this can then be stored in a pointer variable.Arrays are different. The array name is an alias for the start address of the array, thus you do not need the address ofoperator to obtain the memory address (although you can if you want to). This means that when you pass an array name to a function, you pass the memory address of the array rather than passing the array itself (which would require the entire array to be copied, which is a highly inefficient way to pass an array). In essence, the array is passed by reference rather than by value.Consider the following code. This shows how a primitive variable name differs from the name of an array of primitive variables. The final portion shows how a pointer can be used to achieve the same results you got by accessing the array elements directly from the array name itself. This is in fact how the compiler implements arrays, using pointers, but there's no need to do this in your code. Accessing array elements directly by their index is a programming convenience.#include using namespace std;int main(){int i = 10;cout
Pointer to 3 dimensons array?
If the array is static you can simply point at the first element. For dynamic arrays you can allocate a contiguous block to a single pointer which can then be subdivided using a one-dimensional array of pointer to pointers, each of which points to a one-dimensional array of pointers, each of which points to a separate object within the array. For extremely large arrays, however, it is better to split the elements into separate one-dimensional arrays, by creating a one-dimensional array of pointer to pointers first, then allocating each of those pointers to a separate one-dimensional array of pointers, each of which points to a separate one-dimensional array of objects. Either way, you must destroy all the individual arrays in the reverse order of creation.
How do you print array variable without using array subscripts?
Well the most prolific answer to this query would be the use of pointers.Use a pointer and allocate it to the array of interest and start printing.
When does an array behave a pointer?
An array behaves like a pointer when you use its name in an expression without the brackets.int a[10]; /* a array of 10 ints */int *b = a; /* a reference to a as a pointer, making b like a */int c = *(a+3); /* a reference to a[3] using pointer semantics */myfunc(a); /* pass a's address, a pointer to myfunc */Note very carefully that, while an array name and a pointer can almost always be interchanged in context, the are not the same, in that a pointer is an l-value, such as b, above, and can be assigned, whereas a is an r-value and can only be referenced, such as in the same statement, the second statement. Also, an array name does not take up memory, while a pointer does.
What is NULL array in C Language?
There is no "NULL array" as such, you may take a pointer to an array and set it to NULL (binary 0) e.g. int* foo; // Declare a pointer foo = malloc( 40 * sizeof(int)); //Allocate an array of 40 integers pointed to by "foo" foo = NULL; //Set the pointer to NULL, if you're using a garbage collector this should trigger an automatic free() of the memory allocated to the array. If you are NOT using a garbage collector (which is more common in C) this line is a memory leak.
How do you represent binary tree using array?
The root of the tree is stored in array element [0]; for any node of the tree that is stored in array element [i], its left child is stored in array element [2*i], its right child at [2*i+2]
