= (9-6) x (7+1)
9 +16 -1 = 24
9 - 6 = 3 7 + 1 = 8 3 x 8 = 24
How do you add 9, 5, 3, and 1 in such a way to get sum of 21 by using only 6 numbers?You would add 9+5+3+1+1+2 and your answer would be 21.
24 = 9 + 9 + 6
= (9-6) x (7+1)
Use the 1 to flip the 9 upside down.
9 +16 -1 = 24
9 x 5 = 45 - 6 = 39 - 9 = 30 - 1 = 29.I know this and I'm 8!
9 - 6 = 3 7 + 1 = 8 3 x 8 = 24
How do you add 9, 5, 3, and 1 in such a way to get sum of 21 by using only 6 numbers?You would add 9+5+3+1+1+2 and your answer would be 21.
24 = 9 + 9 + 6
1 = 1 2 = 2 3 = 2+1 4 = 6-2 5 = 6-1 6 = 6 7 = 6+1 8 = 6+2 9 = 9 10 = 9+1 11 = 9+2 12 = 9+2+1 13 = 2*6+1 14 = 9+6-1 15 = 9+6 16 = 9+6+1 17 = 9+6+2 18 = 9+6+2+1 19 = 9*2+1 20 = (9+1)*2
3! = 6.
1 plus (6 divided by ((square root of 9) plus (square root of 9))) or 9/(9-6)-1=2
(1 + 8)*sqrt(4*9) = 9*sqrt(36) = 9*6 = 54
(9+1)^(8+7-6-5-4+2+3) = 10^5 = 100,000