1 = 1
2 = 2
3 = 2+1
4 = 6-2
5 = 6-1
6 = 6
7 = 6+1
8 = 6+2
9 = 9
10 = 9+1
11 = 9+2
12 = 9+2+1
13 = 2*6+1
14 = 9+6-1
15 = 9+6
16 = 9+6+1
17 = 9+6+2
18 = 9+6+2+1
19 = 9*2+1
20 = (9+1)*2
(3 + 3) / .3
There are not 20 ways - there are only 12.
Simple! -4-4-4-4-4 = -20
No. There are two reasons why. First, 20 +10+1+1=32, and that does not equel 24. Also you can think of it in a different way. 20 and the three ones (1,1,1) make 23 and that is not 24. You dont pay attention to the zero because zero is not worth anything!!!
They are: 13+7 = 20
101
(22/4)x8-20=24
20 + 20 + 20 + 20 + 20 = 100
(3 + 3) / .3
There are not 20 ways - there are only 12.
Simple! -4-4-4-4-4 = -20
20 is the only number.
To factorise is to find the numbers that divide into the original number by only using prime numbers. For example factorise 20 = 2 times 2 times 5
No. There are two reasons why. First, 20 +10+1+1=32, and that does not equel 24. Also you can think of it in a different way. 20 and the three ones (1,1,1) make 23 and that is not 24. You dont pay attention to the zero because zero is not worth anything!!!
==> 1 x 2 x 4 x 2.5 ==> 1 + 2 + 3 + 14 ==> 10 + 11 + 12 - 13 ==> 1 + 3 + 32/2 Why would you want to use 4 numbers to make one number ? It really seems a lot easier to me to just to just write '20' and be done with it.
They are: 13+7 = 20
A number will always have 1 and itself as factors. And thus the only numbers with 2 factors will be prime numbers. The only prime numbers below 20 are 2, 3, 5, 7, 11, 13, 17 and 19, and thus these are the only numbers below 20 that have 2 factors.