As a solution to the four fours problem (using the number four no more than four times to come up with the solution, 31 is equal to (4!+4)/4+4!
How about: 44-(4/4) = 43
4/.4 + 4/4 = 10 + 1 = 11.
Google "Four Fours" and you will find a number of solutions, presented more comprehensively than we can.
A solution which is accessible with very basic arithmetic and minimal mental effort, is11 = 3/3 +3/3 +3/3 + ... + 3/3 (eleven times, using 22 threes),12 = 3/3 +3/3 +3/3 + ... + 3/3 + 3/3 (twelve times, using 24 threes), and so on.
Four
As a solution to the four fours problem (using the number four no more than four times to come up with the solution, 31 is equal to (4!+4)/4+4!
How about: 44-(4/4) = 43
Only four numbers:20233032
It looks like you're asking what is the largest 4-digit number which has four 4's for digits - with a four digit number using four 4's, there is only one such number: 4444. Maybe I'm not understanding the wording of your question.
Four factorial plus the square root of four minus (four divided by four) 24 + 2 - 1 = 25
145.992 using only four significant figures is 146.0
4*6+1
21,600 using only four significant figures is still 21,600.
4/.4 + 4/4 = 10 + 1 = 11.
Google "Four Fours" and you will find a number of solutions, presented more comprehensively than we can.
A solution which is accessible with very basic arithmetic and minimal mental effort, is11 = 3/3 +3/3 +3/3 + ... + 3/3 (eleven times, using 22 threes),12 = 3/3 +3/3 +3/3 + ... + 3/3 + 3/3 (twelve times, using 24 threes), and so on.