Take the two equations, and line them up with common terms in the same positions:
x - y = 6
x - 2y = 7
In this case, the operation is quite simple because x has no coefficient in either equation. You can simply subtract each term in the latter equation from it's corresponding term in the prior one:
x - y = 6
x - 2y = 7
___________
0 + y = - 1
So we know that y is equal to negative one, and you can solve for x by simply substituting that -1 into either equation:
x - (-1) = 6
x + 1 = 6
x = 5
So x is equal to five, and y is equal to negative one.
If that's x2y and xy2, the GCF is xy.
(b - x)(ab - xy)
x+xy=8 xy=-x+8 y=-1+8/x
If you're solving for x, then x = 3/y.
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
The GCF is xy
To find the greatest common factor of x^2y and xy^2, we need to determine the highest power of each variable that is common to both terms. In this case, the common factors are x and y. The highest power of x that is common to both terms is x^1, and the highest power of y that is common to both terms is y^1. Therefore, the greatest common factor of x^2y and xy^2 is xy.
xy
4
If that's x2y and xy2, the GCF is xy.
(b - x)(ab - xy)
x+xy=8 xy=-x+8 y=-1+8/x
If you're solving for x, then x = 3/y.
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
The GCF of 27 x^2 y^3 and 46 x^2 y is xy^2. 27 and 46 are coprime.
x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
Not sure that there is any name or description. For example, x2y, xy0.5, xy have the same variables but there is no name that encompasses all three.