To solve the equation "what times 4 equals 44," you need to isolate the variable. Let's represent "what" as x. The equation becomes x * 4 = 44. To find the value of x, divide both sides by 4: x = 44 / 4. Therefore, x = 11. So, what times 4 equals 44 is 11.
44 = 9x +8 36=9x 4=x
441
m = 12. 3 x 12 = 36, 36 + 8 = 44.
That won't factor neatly, so we apply the quadratic formula. x = -8 plus or minus 2 times the square root of 5 x = -3.5278640450004204 x = -12.47213595499958
If 6A - 58 = 44 then 6A = 102 making A = 17.
To solve the equation "what times 4 equals 44," you need to isolate the variable. Let's represent "what" as x. The equation becomes x * 4 = 44. To find the value of x, divide both sides by 4: x = 44 / 4. Therefore, x = 11. So, what times 4 equals 44 is 11.
11 times 4 1times 44
44 = 9x +8 36=9x 4=x
441
p = 3209/44
m = 12. 3 x 12 = 36, 36 + 8 = 44.
Solving equations in three unknowns (x, y and z) requires three independent equations. Since you have only one equation there is no solution. The equation can be simplified (slightly) by dividing through by 4 to give: x + 2y + 3z = 11
4x - 9 = 35 4x = 35 + 9 4x = 44 4x/4 = 44/4 x=11
Assuming there is a y missing in the first equation, (A): 0.05x + 0.25y = 44 (B): 0.15x + 0.05y = 48 (C) = 3*(A): 0.15x + 0.75y = 132 Then (C)-(B): 0x + 0.70y = 84 so y = 120 Substituting this value of y in (A) gives 0.05x + 30 = 44 or 0.05x = 14 or x = 280
That won't factor neatly, so we apply the quadratic formula. x = -8 plus or minus 2 times the square root of 5 x = -3.5278640450004204 x = -12.47213595499958
x = -6 or 65x2 - 136 = 445x2 = 180x2 = 36