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Assuming there is a y missing in the first equation,

(A): 0.05x + 0.25y = 44

(B): 0.15x + 0.05y = 48

(C) = 3*(A): 0.15x + 0.75y = 132

Then (C)-(B): 0x + 0.70y = 84 so y = 120

Substituting this value of y in (A) gives 0.05x + 30 = 44 or 0.05x = 14 or x = 280

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Q: Use the elimination method to solve this problem 0.05x plus 0.25 equals 44 0.15x plus 0.05y equals 48?
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