dy/dx = 3^x * ln(3)
integral = (3^x) / ln(3)
To obtain the above integral...
Let y = 3^x
ln y = x ln 3
y = e^(x ln 3)
(i.e. 3^x is the same as e^(x ln 3) ).
The integral will then be 3^x / ln 3 (from linear composite rule and substitution after integration).
If m equals 3 then m to the 6th power (m6) equals 36 or 3 x 3 x 3 or 27
a, a^3*a^-2 is a^3+-2 which equals just a
10 to the power 3 = 1000
It is: 19^3 = 6859
512
dy/dx = 3 integral = (3x^2)/2
I can't integrate a-x /x-3 ?
integrate(x5x dx) simplifies to integrate(5x^2 dx), and using the power rule of integration, add one to the power of x and divide the term by that number. Thus, x5x dx integrated is (5/3)x^3
If m equals 3 then m to the 6th power (m6) equals 36 or 3 x 3 x 3 or 27
a, a^3*a^-2 is a^3+-2 which equals just a
10 to the power 3 = 1000
2 to the power of 3 equals 8.
2 to the power of -3 equals 0.125
3 to the 3rd power + 3 to the 3rd power = 54
3 to the ninth power equals 19,683 while 9 to the fourth power equals 6,561 (if i'm not mistaken) so.. 9 to the fourth power (<) 3 to the ninth power
2 to the power of -3 equals 0.125
log 3 is a constant, so d/dx log3, like d/dx of any constant, equals zero.