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How do you Find the equation of a parabola with the vertex x equals -2 y equals -5 and passes through x equals 4 y equals -1?
(X +2)^2 - 5 = 0
X = - 4, Y = - 1
--------------------------- for intercepts
Just read it.
y = x2 +4x -1 (the standard form)
Since the vertex is (-2, -5), x = -2 is the equation of the axis of symmetry, also b= 4a (-b/2a = -2).
Since the parabola passes through (-4, -1) it also will passes through (0, -1), it means that c (y-intercept) equals to -1.
So we have,
y = ax2 + 4ax - 1 (replace x with -2, and y with -5)
-5 = 4a - 8a - 1
-4 = -4a
1 = a so that b = 4
What else can I help you with?
What is the equation for the parabola with the vertex -3.0 that passes through the point 318?
To find the equation of a parabola with vertex at ((-3, 0)) that passes through the point ((3, 18)), we can use the vertex form of a parabola, (y = a(x + 3)^2). To determine the value of (a), substitute the point ((3, 18)) into the equation: [ 18 = a(3 + 3)^2 \implies 18 = a(6)^2 \implies 18 = 36a \implies a = \frac{1}{2}. ] Thus, the equation of the parabola is (y = \frac{1}{2}(x + 3)^2).
What shape is y equals 3 times x to the second power?
It is a parabola, which passes through the origin and is symmetric about the y axis.
What is the primary focal chord of a parabola?
The primary focal chord of a parabola is a line segment that passes through the focus of the parabola and has its endpoints on the parabola itself. For a standard parabola defined by the equation (y^2 = 4px), the focus is located at the point ((p, 0)). The primary focal chord is unique in that it is perpendicular to the axis of symmetry of the parabola and is the longest chord that can be drawn through the focus.
Enter an equation of the form y equals mx for the line that passes through the origin and has slope 2?
UndefinedImproved Answer:-The straight line equation is: y = 2x
Enter an equation of the form y equals mx for the line that passes through the origin and has slope 1?
y=x
What is the equation for the parabola with the vertex -3.0 that passes through the point 318?
To find the equation of a parabola with vertex at ((-3, 0)) that passes through the point ((3, 18)), we can use the vertex form of a parabola, (y = a(x + 3)^2). To determine the value of (a), substitute the point ((3, 18)) into the equation: [ 18 = a(3 + 3)^2 \implies 18 = a(6)^2 \implies 18 = 36a \implies a = \frac{1}{2}. ] Thus, the equation of the parabola is (y = \frac{1}{2}(x + 3)^2).
What is an equation of the parabola in vertex form that passes through (13 8) and has vertex (3 2).?
please help
What shape is y equals 3 times x to the second power?
It is a parabola, which passes through the origin and is symmetric about the y axis.
What is the primary focal chord of a parabola?
The primary focal chord of a parabola is a line segment that passes through the focus of the parabola and has its endpoints on the parabola itself. For a standard parabola defined by the equation (y^2 = 4px), the focus is located at the point ((p, 0)). The primary focal chord is unique in that it is perpendicular to the axis of symmetry of the parabola and is the longest chord that can be drawn through the focus.
Enter an equation of the form y equals mx for the line that passes through the origin and has slope 2?
UndefinedImproved Answer:-The straight line equation is: y = 2x
Enter an equation of the form y equals mx for the line that passes through the origin and has slope 13?
y=13x
Enter an equation of the form y equals mx for the line that passes through the origin and has slope 1?
y=x
What is the equation of a line that passes through the point 4 7 and is parallel to the Y equals 5?
The equation of a line that is parallel to ( y = 5 ) will have the same slope, which is 0, indicating a horizontal line. Since it passes through the point (4, 7), the equation of the line is simply ( y = 7 ).
What is the parabola equation?
the equation of a parabola is: y = a(x-h)^2 + k *h and k are the x and y intercepts of the vertex respectively * x and y are the coordinates of a known point the curve passes though * solve for a, then plug that a value back into the equation of the parabola with out the coordinates of the known point so the equation of the curve with the vertex at (0,3) passing through the point (9,0) would be.. 0 = a (9-0)^2 + 3 = 0 = a (81) + 3 = -3/81 = a so the equation for the curve would be y = -(3/81)x^2 + 3
Which quadrant does the reprenting the equation y equals -3x pass through?
It passes through Quadrants II and IV. It also passes through the origin ... the point where the 'x' and 'y' axes cross. At that point, it's in all four quadrants.
The vertex of this parabola is at 3 1 When the y-value is 0 the x-value is 4 What is the coefficient of the squared term in the parabolas equation?
To find the coefficient of the squared term in the parabola's equation, we can use the vertex form of a parabola, which is (y = a(x - h)^2 + k), where ((h, k)) is the vertex. Given the vertex at (3, 1), the equation starts as (y = a(x - 3)^2 + 1). Since the parabola passes through the point (4, 0), we can substitute these values into the equation: (0 = a(4 - 3)^2 + 1), resulting in (0 = a(1) + 1). Solving for (a), we find (a = -1). Thus, the coefficient of the squared term is (-1).
What is the equation of the line that passes through 3 4 and is parallel to the whose equation is y equals 3x - 2?
y -4 = 3(x-3)y = 3x -5
