x(x + 2)
(x - 6) (x + 4) = x2 - 2x - 24
Write it as x2 - 2x - 4 = 0, and solve with the quadratic formula (a = 1, b = -2, c = -4).
To simplify the expression ((1x^2 - 2x + 4) + (2x + 1) - (x^2 + 5)), first combine like terms. The (x^2) terms give (1x^2 - 1x^2 = 0). The (x) terms yield (-2x + 2x = 0), and the constant terms combine to (4 + 1 - 5 = 0). Thus, the simplified expression is (0).
x2-2x-24 when factorised = (x+4)(x-6)
Factor it out: (x+2) squared
x(x + 2)
(x2+3x-4) (x-4)
(x - 6) (x + 4) = x2 - 2x - 24
2(x + 2)(x - 2)(x2 + 2x + 4)(x2 - 2x + 4)
2X divided by 4= 2X
Write it as x2 - 2x - 4 = 0, and solve with the quadratic formula (a = 1, b = -2, c = -4).
To simplify the expression ((1x^2 - 2x + 4) + (2x + 1) - (x^2 + 5)), first combine like terms. The (x^2) terms give (1x^2 - 1x^2 = 0). The (x) terms yield (-2x + 2x = 0), and the constant terms combine to (4 + 1 - 5 = 0). Thus, the simplified expression is (0).
x2-2x-24 when factorised = (x+4)(x-6)
x2 - 2x - 24 = (x - 6)(x + 4)
If that's + 8x, the answer is 4(x2 + 2x - 6) If that's - 8x, the answer is 4(x2 - 2x - 6)
negative four: x2 - 2x + 5 = x2 - 2x + 5 - 4 = x2 - 2x + 1 = (x - 1)2