(3x - y)(3x - 5y) and (2x + 1)(2x + 11)
3xy3
1/5y2+9
If y = 2x+1 is a tangent line to the circle 5y^2 +5x^2 = 1 then the point of contact is at (-2/5, 1/5) because it has equal roots
10y2 - 15y2 = -5y2
(3x - y)(3x - 5y) and (2x + 1)(2x + 11)
3xy3
1/5y2+9
3xy3
If y = 2x+1 is a tangent line to the circle 5y^2 +5x^2 = 1 then the point of contact is at (-2/5, 1/5) because it has equal roots
The GCF is 5y.20y3 = (5y)(4y2)5y2 = (5y)(y)45y = (5y)(9)
10y2 - 15y2 = -5y2
x5y2 - 2 = 0 ... makes sense
(5y + 3)(y - 1)
That is the most simplifiable version of this equation.
Multiply each item by 10 to give whole numbers then move items to give ay2+by+c=0 3.5y2+2.6y-8.2=4y2-6.9y multiply by 10 35y2 + 26y - 82 = 40y2 -69y subtract 35y2 from both sides 26y - 82=5y2 -69y subtract 26y from both sides -82 = 5y2 - 95y add 82 to each side 0 = 5y2 - 95y +82 or 5y2 - 95y +82 = 0
it's MINUS 182.5