answersLogoWhite

0


Best Answer

x5y2 - 2 = 0

... makes sense

User Avatar

Wiki User

∙ 13y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Is x 5y2 - 2 a function?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Calculus

What is the integral of mod x function?

The integral of the absolute value function, |x|, is given by the piecewise function ∫|x|dx = (x^2)/2 + C for x ≄ 0 and ∫|x|dx = (-x^2)/2 + C for x < 0, where C is the constant of integration. This is because the absolute value function changes its behavior at x = 0, resulting in two different expressions for the integral depending on the sign of x.


What is the range of a a function f when it is defined by f x 2 cos 3 x where x is a real number?

f(x) = 2 cos 3x The amplitude: A = |2| = 2 The maximum value of the function: 2 The minimum value of the function: -2 The range: [-2, 2]


What is the domain of the function f x x 2 plus 4?

The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)


What is a rational function graph?

The Equation of a Rational Function has the Form,... f(x) = g(x)/h(x) where h(x) is not equal to zero. We will use a given Rational Function as an Example to graph showing the Vertical and Horizontal Asymptotes, and also the Hole in the Graph of that Function, if they exist. Let the Rational Function be,... f(x) = (x-2)/(x² - 5x + 6). f(x) = (x-2)/[(x-2)(x-3)]. Now if the Denominator (x-2)(x-3) = 0, then the Rational function will be Undefined, that is, the case of Division by Zero (0). So, in the Rational Function f(x) = (x-2)/[(x-2)(x-3)], we see that at x=2 or x=3, the Denominator is equal to Zero (0). But at x=3, we notice that the Numerator is equal to ( 1 ), that is, f(3) = 1/0, hence a Vertical Asymptote at x = 3. But at x=2, we have f(2) = 0/0, 'meaningless'. There is a Hole in the Graph at x = 2.


When the zeros of a polynomial function are 1 divided by2 and negative 1 what is the function?

Any multiple of X^2+X/2-1/2

Related questions

X equals 5y2-20y plus 15?

x isn't in the calculation so it cant be solved.


What is the recoprocal of 5y2 plus 9y?

1/5y2+9


How do you expand an equation?

Multiply the coefficient by all the values inside the brackets.Example 1:2(y+1)= 2 X y + 2 X 1= 2y + 2Example 2:3 X 5y(y+4)= 3 X (5y X y) + (5y X 4)= 3 X 5y2 + 20y


What is another name for the root of a function?

The "root" of a function is also called the "zero" of a function. This is where the function equals zero. The function y=4-x2 has roots at x=2 and x=-2 The function y=4-x2 has zeroes at x=2 and x=-2 Those are equivalent statements.


Is it true or false that the limit of a function f x at x equals 2 is always the value of the function at x equals 2 that is f 2?

False. It is true for a function that is continuous at x=2, but it is not generally true for all functions. For a counterexample, consider the function f(x), such that: f(x)=x for x not equal to 2 f(x)=0 for x=2 The limit of this function as x approaches 2 is 2 (since we can make f(x) as close to 2 as we want as x gets closer to 2), but f(2) does not equal the limit of f(x) as x approaches 2.


f(x)= – x2fâ€Čâ€Č(x)=?

The function given is (f(x) = -x^2). The second derivative of a function, denoted as (f’'(x)), measures the concavity of the function. For the function (f(x) = -x^2), the first derivative (f’(x)) is (-2x). Taking the derivative of (f’(x)) gives us the second derivative (f’‘(x)), which is (-2). So, (f’'(x) = -2). This indicates that the function (f(x) = -x^2) is concave down for all (x), because the second derivative is negative.


How would you prove algebraically that the function f(x) x-2 x 2 is one to one?

How would you prove algebraically that the function: f(x)= |x-2|, x<= 2 , is one to one?


What is the integral of mod x function?

The integral of the absolute value function, |x|, is given by the piecewise function ∫|x|dx = (x^2)/2 + C for x ≄ 0 and ∫|x|dx = (-x^2)/2 + C for x < 0, where C is the constant of integration. This is because the absolute value function changes its behavior at x = 0, resulting in two different expressions for the integral depending on the sign of x.


What is the range of a a function f when it is defined by f x 2 cos 3 x where x is a real number?

f(x) = 2 cos 3x The amplitude: A = |2| = 2 The maximum value of the function: 2 The minimum value of the function: -2 The range: [-2, 2]


What does function of x mean?

A function of x means that the answers depends on the value of x that is substituted into the function. For example: y = x + 1 If x = 1, y = 2 If x = 2, y = 3 and so on.


What is the domain of the function f x x 2 plus 4?

The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)


How do you factor out x squared plus 8xy plus 15y squared?

x2 + 8xy + 15y2 = (x + 3y) (x + 5y)