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If you have a non-scientific calculator you can use the Newton-Raphson method.

Suppose you wish to find the square root of 7.

Let f(x) = x2 - 7 so that f(x) = 0 when x is the square roo. That is, you want to find x such that f(x) = 0.

Let f'(x) = 2x

[f'(x) is the derivative of f(x) but you do not need to know that to use the N-R method.]

Make a guess at the square root of 7, and call is x0.

Then calculate

xn+1 = xn - f(xn)/f'(xn) for n = 1, 2, 3, ...

Provided you made a reasonable choice for the starting point, the iteration will very quickly converge to the true answer. Even if your first guess is not so good:

Suppose you start with x0 = 5 (a pretty poor choice since 52 is 25, which is nowhere near 7).

Even so, x3 = 2.2362512515, which is less than 0.01% from the true value. Finally, remember that the negative value is also a square root.

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Q: How do you approximate the square root?
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